Answer:
The angle through which the wheel turned is 947.7 rad.
Explanation:
initial angular velocity,
= 33.3 rad/s
angular acceleration, α = 2.15 rad/s²
final angular velocity,
= 72 rad/s
angle the wheel turned, θ = ?
The angle through which the wheel turned can be calculated by applying the following kinematic equation;

Therefore, the angle through which the wheel turned is 947.7 rad.
Answer:
200 m\ s Ans .....
Explanation:
Data:
f = 200 Hz
w = 1.0 m
v = ?
Formula:
v = f w
Solution:
v = ( 200)(1.0)
v = 200 m\s <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
<h2>Answer:</h2>
<u>The correct option is</u><u> (C) its greater tensile strength </u>
<h2>Explanation:</h2>
Elasticity is the property of any material to return to its original shape when it is de-shaped. for example a spring comes to its original shape when it is stretched and then released. so the property that brings the spring back to its original form is called elasticity. On the other hand tensile strength is the maximum stress that a material can withstands before it breaks. Since polymers are also elastic so the greater tensile strength means greater elasticity.
Answer:
a) i) x = 0.25 m, ii) x = 0.10 m, iii) x = 0.050 m
b) i) x = 0.40 m
Explanation:
a) For this exercise we use the rotational equilibrium equation, where we assume that the anticlockwise rotations are positive.
1) L = 2W
we set our reference system in the center of the bar where the fulcrum is
∑τ = 0
W 0.50 - L x = 0
x = 0.50 W / L
we substitute the value
x = 0.50 W / 2W
x = 0.25 m
ii) L = 5W
we calculate
x = 0.50 W / 5W
x = 0.10 m
iii) L = 10 W
x = 0.50 W / 10W
x = 0.050 m
b) a new weight is placed at x₂ = 30 cm on the left side
W 0.50 + W 0.30 - L x = 0
x = (0.50 + 0.30) W / L
x = 0.80 W / L
we calculate
i) L = 2W
x = 0.80 w / 2w
x = 0.40 m