The final atmospheric pressure is 
Explanation:
Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

where
p is the gas pressure
V is the volume
The equation can also be rewritten as

where in our problem we have:
is the initial pressure (the atmospheric pressure at sea level)
is the initial volume
is the final pressure
is the final volume
Solving the equation for p2, we find the final pressure:

Learn more about ideal gases:
brainly.com/question/9321544
brainly.com/question/7316997
brainly.com/question/3658563
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8 tablespoons of water.
2 x 4 = 8
I hope this helps :)
Answer:
2.96 cm
Explanation:
By Hook's law
Force(F) = Spring constant(k) × Extension(d)
F = k × d
Force is the weight of the object, F = W = mg
So we get, mg = kd ⇒ m ∝ d
2.5 ∝ 1.68 --------------(1)
4.4 ∝ d' --------------(2)
From (1) & (2), 4.4/2.5 = d'/1.68
d' = 2.96 cm ⇒ the required extension.
Answer:
70 cm
Explanation:
0.5 kg at 20 cm
0.3 kg at 60 cm
x = Distance of the third 0.6 kg mass
Meter stick hanging at 50 cm
Torque about the support point is given by (torque is conserved)

The position of the third mass of 0.6 kg is at 20+50 = 70 cm
.........,....,,,???........