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lora16 [44]
2 years ago
10

A weightlifter completes a series of lifts with a 700 N weight. In one lift, he raises the weight to a height of 2.5 m off the g

round. The lift takes 0.60 s to complete. What power does the weightlifter have been performing this lift
Physics
1 answer:
zhannawk [14.2K]2 years ago
5 0

Answer:

The output power the weightlifter is 2916.67 W.

Explanation:

Given;

weight lifted, W = 700 N

height the weight is lifted, h = 2.5 m

time taken to lift the weight, t = 0.60 s

The output power the weightlifter is calculated as;

Power = Energy applied / time taken

Energy applied = weight lifted x height the weight is lifted

Energy applied = 700 x 2.5

Energy applied = 1750 J

Power = 1750 / 0.6

Power = 2916.67 J/s = 2916.67 W.

Therefore, the output power the weightlifter is 2916.67 W.

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Using a rope that will snap if the tension in it exceeds 356 N, you need to lower a bundle of old roofing material weighing 478
klasskru [66]

Answer:

a) 2.5 m/s²

b) 6.12 m/s

Explanation:

Tension of rope = T = 356N

Weight of material = W = 478 N

Distance from the ground = s = 7.5 m

Acceleration due to gravity = g = 9.81 m/s²

Mass of material = m = 478/9.81 = 48.72

Final velocity before the bundle hits the ground = v

Initial velocity = u = 0

Acceleration experienced by the material when being lowered = a

a) W-T = ma

⇒478-356 = 48.72×a

\Rightarrow \frac{122}{48.72} = a

⇒a = 2.5 m/s²

∴ Acceleration achieved by the material is 2.5 m/s²

b) v²-u² = 2as

⇒v²-0 = 2×2.5×7.5

⇒v² = 37.5

⇒v = 6.12 m/s

∴ Velocity of the material before hitting the ground is 6.12 m/s

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Explanation:

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If I understand correctly. Line B is parallel to the circle. Also, the angle is less than 90.

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Explanation: In order to calculate the electric field from long wire we have to use the Gaussian law, this is:

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