Otal energy= PEmax on the spring = KEmax of the oject
<span>Total Energy= KE+PE at v or x not maximum. </span>
<span>Using the second line </span>
<span>E= 3/4 E + PE </span>
<span>PE = 1/4 E </span>
<span>PEmax =E = 1/2 kA^2 </span>
<span>PE=E/4 = (1/2)kA^2 / 4= kA^2/8
</span>
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Answer:
the apparent weight of the astronaut in the rocket is 3723 N.
Given:
acceleration = 34 
mass of astronaut = 85 kg
To find:
Apparent weight of the astronaut = ?
Solution:
Total weight of the astronaut in a rocket is given by,
W = w + F
W = apparent weight of the astronaut
w = weight of astronaut on earth surface = mg
F = force acting on the astronaut = ma
W = mg+ma
W = m (g+a)
W = 85 (9.8 + 34)
W = 3723 N
Thus, the apparent weight of the astronaut in the rocket is 3723 N.
To determine the number of gold bars that would fit in the vault, determine the volume (v) of a single gold bar.
v = l x h x w
where l, h, and w are length, height and width, respectively. Substituting the known values,
v = (6 cm)(2 cm)(3 cm) = 36 cm³
The number of gold bars can be determined by dividing the volume of the vault by the volume of the gold bar,
n = (500 cm³ / 36 cm³) = 13.89
Thus, the maximum number of gold bars in the vault is 13.
