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3 years ago

Which is true of Saturn's satellite, Titan?

Chemistry

1 answer:

KatRina [158]3 years ago

8 0

Answer:

D. It may be similar to Earth's early conditions.

Explanation:

Titan is one of the many satellites orbiting planet saturn. This satellite is very interesting as it shows a lot of similarities with the conditions at play when the early earth formed.

The early earth atmosphere was made up of reduced gases lacking in oxygen. Titan's atmosphere also share this similarity. It's atmosphere is predominantly made up of nitrogen, methane and carbon dioxide.

Titan also has a rocky surface just like earth and it has an atmospheric cover.

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What periodic pattern are noticed for the charges on the ions

Vadim26 [7]

charge of elements increases by one as you move from left to right.

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3 years ago

Which of the following solutions is a buffer? Which of the following solutions is a buffer? a solution of sulfuric acid and sodi

Sever21 [200]

Answer:

a solution of acetic acid and sodium acetate

Explanation:

A buffer solution is defined as a solution which resist a change in pH when small quantity of a strong acid or a strong base are added. A buffer solution is made up of mixture of a weak acid and its conjugate base or a mixture of a weak base and its conjugate acid.

Acetic acid is the only option because it is a weak acid with a corresponding conjugate base, acetate. Unlike a solution of sulfuric acid and sodium sulfate in which the sulfuric acid is a strong acid which doesn’t qualify it to be a buffer solution. The remaining options have different acid compounds paired together which makes them invalid too.

4 0

3 years ago

If you were asked to run Spartan calculations on the C2H3O2-/H3O ion pair, the trend in the resulting data points would appear s

Taya2010 [7]

Answer:

a. True

Explanation:

The data curve for OCI-/H3O appears to be similar to C2H3O2-/H3O because protons have not dissociated with conjugate base. This conjugate base is strong and hold proton in solution while acids try to dissociate it.

4 0

3 years ago

Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to

Bess [88]

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density $\rho_{avg}$ ; we have:

$\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$

The average atomic weight is:

$A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$

So; in terms of vanadium, the Concentration of iron is:

$C_{Fe} = 100 - C_v$

From a unit cell volume $V_c$

$V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}$

where;

$N_A$ = number of Avogadro constant.

SO; replacing $V_c$ with $a^3$ ; $\rho_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$ ; $A_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$ and

$C_{Fe}$ with $100-C_v$

Then:

$a^3 = \dfrac { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) } {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big) }$

Replacing the values; we have:

$(0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol) } }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3) } }$

$2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} } \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }$

$2.41 \times 10^{-23} (\dfrac{4704}{600+1.84 C_v})=3.2 \times 10^{-24} ( \dfrac{284448.96}{5094 +4.9 C_v})$

$\mathbf{C_v = 9.1 \ wt\%}$

4 0

3 years ago

What term describes gas that is compressed into a smaller space than it would normally occupy at Earth's surface?

Aloiza [94]

Pressurized gas is the term that is used to describe a gas that is compressed into a smaller space than it would normally occupy at Earth's surface.

Explanation:

The purpose of compressing a gas is to lessen its volume so that it can fit in a small space. Natural gas can be compressed using a compressor and the pressure of a compressed gas is 200 to 250 bars.

Pressurized gases are used in ground processing and space flight operations. Pressurized gas, also known as compressed gas is also used in fuel production and in gas pipelines.

When stored in a reservoir, care must be taken to avoid leakage as these gases compressed under high pressure are highly flammable.

8 0

3 years ago