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Agata [3.3K]
3 years ago
13

What is the functional group of a carboxylic acid?

Chemistry
1 answer:
Talja [164]3 years ago
4 0

Answer:

A. Carbon double bonded to oxygen and a hydroxyl group (OH).

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Explain why Ra is larger than Be. With 2 points.
igor_vitrenko [27]

Explanation:

<h2>Radium(Ra)=> </h2>

atomic number=88

<h2>BERYLLIUM (Be)=></h2>

atomic number =4

why is Ra larger than Be

<h3>1. since the atomic number of Ra is greater than Be, the number of electrons is more, which means there are more number of shells present in Ra than Be. </h3><h2>(atomic Radius)</h2>

<h2>2. the more the valence electron (excluding fully filled ones) the less is the nuclear attraction force</h2><h3>since Ra has more valence electron in its outermost shell, the nuclear attraction force is less which means that Ra 's size is greater than Be.</h3>

hope it helps:)

6 0
3 years ago
Calculate the density of mercury of it pours exactly 22.5 mL into a graduated cylinder and has a mass of 316 g.
Rasek [7]
Density = mass/volume = 316/22.5 = 14.045g/mL. 
8 0
3 years ago
I’ll mark you brainley if you help me figure out which answer it is!!!
Stolb23 [73]

Answer:

A

Explanation:

A chemical change happens when one chemical substance is transformed into one or more different things , such as when iron becomes rust so

B: Acids turn the indicator red, pink, orange, and yellow, while bases turn it green based on what it reactions with or comes in contact with  so b is maybe

c is wrong

and d a physical change, will technically yes and no there should have not been a smell afterwards so the only really choose that makes sense here is A  

5 0
3 years ago
How does this graph illustrate Boyle’s law?
bazaltina [42]
Do you have a picture of the graph?
5 0
3 years ago
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq
____ [38]

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

P\cdot V = k (1)

Where:

P - Pressure, in kilopascals.

V - Volume, in cubic centimeters.

k - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

\dot P \cdot V + P\cdot \dot V = 0 (2)

Where:

\dot P - Rate of change of the pressure, in kilopascals per minute.

\dot V - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

P\cdot \dot V = -\dot P\cdot V

\dot V = -\left(\frac{\dot P}{P} \right) \cdot V

If we know that P = 180\,kPa, \dot P = 30\,\frac{kPa}{min} and V = 300\,cm^{3}, then the rate of change of the volume is:

\dot V = -\left(\frac{\dot P}{P} \right) \cdot V

\dot V = -50\,\frac{cm^{3}}{min}

The gas is decreasing at a rate of 50 cubic centimeters per minute.

3 0
3 years ago
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