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Irina-Kira [14]
3 years ago
9

If mass increases what must happen to the force in order to achieve the same change in motion

Chemistry
1 answer:
kkurt [141]3 years ago
8 0

Answer:

the force has to increase aswell

Explanation:

force and mass have a direct relationship meaning when one increases the other will. the heavier something is, the more force u have to put in order to get it to move!!

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Consider the following list of liquids and their boiling points: ether, bp = 35°C acetone, bp = 56°C cyclohexane, bp = 80°C wate
SVEN [57.7K]

Answer:

Ether

Explanation:

NB: The boiling point of the liquids given are referred to as their normal boiling point i.e the boiling point at atmospheric pressure.

The relationship between normal Boiling point and vapor pressure is that; at a given temperature the lower the normal boiling point, the higher the vapor pressure.

hence ether with the least normal boiling point of 35°C is expected to have the largest vapor pressure near room temperature.

8 0
3 years ago
What words do scientists use to classify their ideas?
Ipatiy [6.2K]

Answer:

Scientists use a two-name system called a Binomial Naming System. Scientists name animals and plants using the system that describes the genus and species of the organism. The first word is the genus and the second is the species. The first word is capitalized and the second is not.

Explanation:

3 0
3 years ago
Define the following:
Advocard [28]

Answer:

A. Passive Transport is migration of a molecule from one side of the cell membrane to the other, from an area of high electrochemical potential to a region of lower electrochemical potential.

B. Diffusion is an individual molecule of a material moving from a high-concentration location to a low-concentration area over a semipermeable barrier

C. Osmosis is the movement of molecules of water through a cell's partly permeable membrane from a liquid with a large concentration of water molecules to a solution with a lower concentration of water molecules.

D. Facilitated Diffusion are molecules that diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers.

E. Active transport is the transport of molecules across a cell membrane against a concentration gradient from a low-concentration region to a high-concentration region.

F. Selectively permeable is when some chemicals or ions pass across the membrane, while others are blocked.

G. Cellular respiration are organisms mix oxygen with food molecules, directing the chemical energy in these substances into life-sustaining processes while eliminating carbon dioxide and water as waste material.

Explanation:

8 0
2 years ago
Question 1(Multiple Choice Worth 4 points)
zubka84 [21]

<u>Answer </u>

Answer 1 : 28.9 g of CO is needed.

Answer 2 : Six moles of H_{2}O over Nine moles of O_{2}

Answer 3 : Four over two fraction can be used for the mole ratio to determine the mass of Fe from a known mass of Fe_{2}O_{3}.

Answer 4 : Mass of O_{2} = (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Answer 5 : 8.4 moles of sodium cyanide (NaCN) would be needed.

<u>Solution </u>

Solution 1 : Given,

Given mass of Fe_{2}O_{3} = 55 g

Molar mass of Fe_{2}O_{3} = 159.69 g/mole

Molar mass of CO = 28.01 g/mole

Moles of Fe_{2}O_{3} = \frac{\text{ Given mass of } Fe_{2}O_{3}}{\text{ Molar mass of } Fe_{2}O_{3}} = \frac{55 g}{159.69 g/mole} = 0.344 moles

Balanced chemical reaction is,

Fe_{2}O_{3}(s)+3CO(g)\rightarrow 2Fe(s)+3CO_{2}(g)

From the given reaction, we conclude that

1 mole of Fe_{2}O_{3} gives              →         3 moles of CO

0.344 moles of Fe_{2}O_{3} gives    →         3 × 0.344 moles of CO

                                                     =         1.032 moles

Mass of CO = Number of moles of CO × Molar mass of CO

                    = 1.032 × 28.01

                    = 28.90 g

Solution 2 : The balanced chemical reaction is,

2C_{3}H_{6}+9O_{2}\rightarrow 6CO_{2}+6H_{2}O

From the given reaction, we conclude that the Six moles of H_{2}O over Nine moles of O_{2} is the correct option.

Solution 3 : The balanced chemical reaction is,

4Fe+3O_{2}\rightarrow 2Fe_{2}O_{3}

From the given balanced reaction, we conclude that Four over two fraction can be used for the mole ratio to determine the mass of Fe from a known mass of Fe_{2}O_{3}.

Solution 4 : Given,

Given mass of Zn(ClO_{3})_{2} = 150 g

Molar mass of Zn(ClO_{3})_{2} = 232.29 g/mole

Molar mass of O_{2} = 31.998 g/mole

Moles of Zn(ClO_{3})_{2} = \frac{\text{ Given mass of }Zn(ClO_{3})_{2} }{\text{ Molar mass of } Zn(ClO_{3})_{2}} = (\frac{150\times 1}{232.29})moles

The balanced chemical equation is,

Zn(ClO_{3})_{2}}\rightarrow ZnCl_{2}+3O_{2}

From the given balanced equation, we conclude that

1 mole of Zn(ClO_{3})_{2} gives          →       3 moles of O_{2}

(\frac{150\times 1}{232.29})moles of Zn(ClO_{3})_{2} gives  →  [(\frac{150\times 1}{232.29})\times 3] moles of O_{2}

Mass of O_{2} = Number of moles of O_{2} × Molar mass of  O_{2} = [(\frac{150\times 1}{232.29})\times 3] \times 31.998 grams

Therefore, the mass of O_{2} = (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Solution 5 : Given,

Number of moles of Na_{2}SO_{4} = 4.2 moles

Balanced chemical equation is,

H_{2}SO_{4}+2NaCN\rightarrow 2HCN+Na_{2}SO_{4}

From the given chemical reaction, we conclude that

1 mole of Na_{2}SO_{4} obtained from 2 moles of NaCN

4.2 moles of Na_{2}SO_{4} obtained   →   2 × 4.2 moles of NaCN

Therefore,

The moles of NaCN needed = 2 × 4.2 = 8.4 moles


3 0
3 years ago
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100 points! Report on an element
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Hydrogen  H weight: 81

Non-metal

Hydrogen is the simplest element; an atom consists of only one proton and one electron. It is also the most plentiful element in the universe. Despite its simplicity and abundance, hydrogen doesn't occur naturally as a gas on the Earth--it is always combined with other elements.

period 1 group 1

Hydrogen is easily the most abundant element in the universe. It is found in the sun and most of the stars, and the planet Jupiter is composed mostly of hydrogen. On Earth, hydrogen is found in the greatest quantities as water.

6 0
3 years ago
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