The investigation using solid and liquid water to show that thermal energy is not the same as temperature is:
- Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.
<h3>What is the response to the experiment above?</h3>
The response is No, because the lake is known to have a lot more particles than the glass of water and so they will not have the same thermal energy.
Note that the temperature is seen as the an average and thermal energy is seen to be the total. A glass of water can be able to have the same temperature as what we call Lake Superior, but the lake has a lot of thermal energy due to the fact that the lake has a lot of water molecules.
So the investigation using solid and liquid water to show that thermal energy is not the same as temperature is Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.
Learn more about thermal energy from
brainly.com/question/19666326
#SPJ1
We need to increase the concentration of common ion first, in order to promote the common ion effect
<h3>What is the Common ion effect?</h3>
It is an effect that suppresses the dissociation of salt due to the addition of another salt having common ions.
For example, a saturated solution of silver chloride in equilibrium has Ag⁺ and Cl⁻ . Sodium Chloride is added to the solution and has a common ion Cl⁻. As a result, the equilibrium shifts to the left to form more silver chloride. Thus, solubility of AgCl decreases.
The Equilibrium law states that if a process is in equilibrium and is subjected to a change
- in temperature,
- pressure,
- the concentration of reactant or product,
then the equilibrium shifts in a particular direction, according to the condition.
Thus, an increase in the concentration of common ion promotes the common ion effect.
Learn more about common ion effect:
brainly.com/question/23684003
#SPJ4
Hello!
Find the Energy of the Photon by Planck's Equation, given:
E (photon energy) =? (in Joule)
h (Planck's constant) = 
f (radiation frequency) =
Therefore, we have:





I Hope this helps, greetings ... DexteR! =)