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3 years ago

Can you show the work for (4x-4)(x-4)

Mathematics

1 answer:

Paladinen [302]3 years ago

6 0

Answer:

4x² - 20x + 16

Step-by-step explanation:

Given

(4x - 4)(x - 4)

Each term in the second factor is multiplied by each term in the first factor, that is

4x(x - 4) - 4(x - 4) ← distribute both parenthesis

= 4x² - 16x - 4x + 16 ← collect like terms

= 4x² - 20x + 16

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A dress needs 3 1/4 yards of fabric to make. If the matching jacket requires 5/6 less yards of fabric. How much fabric is needed

oksian1 [2.3K]

Fabric needs to make a dress = 3 1/4
fabric needs to make jacket= 3 1/4 - 5/6
= 29/12 or 2 5/12
Hence total fabric needed for both pieces is
= 3 1/4 + 2 5/12
= 68/12 or 5 8/12 or 5 2/3 yards

3 0

3 years ago

Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options. 8(x2 + 2x +

AnnyKZ [126]

The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.

<h3>Quadratic equation</h3>

8x² + 16x + 3 = 0

8x² + 16x = -3

8(x² + 2x) = -3

Using completing the square

8(x² + 2x + 1) = -3 + 8

factorization

8(x² + 1) = 5

(x² + 1) = 5/8

Taking the square root of both sides

(x + 1) = ± √5/8

x = -1 ± √5/8

Therefore,

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

Learn more about quadratic equation:

brainly.com/question/1214333

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4 0

2 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial: