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2 years ago

Can you show the work for (4x-4)(x-4)

Mathematics

1 answer:

Paladinen [302]2 years ago

6 0

Answer:

4x² - 20x + 16

Step-by-step explanation:

Given

(4x - 4)(x - 4)

Each term in the second factor is multiplied by each term in the first factor, that is

4x(x - 4) - 4(x - 4) ← distribute both parenthesis

= 4x² - 16x - 4x + 16 ← collect like terms

= 4x² - 20x + 16

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mafiozo [28]

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2 years ago

Find the rate of 250mm to 75cm

Kruka [31]

If you’re looking for the ratio:

75cm = 750mm

250:750
1:3

The answer is 1:3

6 0

1 year ago

In triangle XYZ, an exterior angle to angle X had measure 100° and an exterior angle to angle Z has measure 120°. Which side of

DaniilM [7]

Answer:

Side YZ is the longest

Step-by-step explanation:

The longest side is across from the largest angle.

Angle X must be 80° because its exterior angle is 100° and they're supplementary. Angle Z is 60° for the same reason. Inside a triangle is always 180°, and since the measures of angle Z and X add up to 140°, so there's 40° left, meaning angle X is the largest.

Angle X is across from size YZ, so that's the longest

5 0

2 years ago

If a triangle has a height of 12 inches and a base of 5 inches, what is its area

Alina [70]

Area of a Triangle = base * height

Area = 12 inches * 5 inches

Area = 60 inches²

4 0

2 years ago

Read 2 more answers

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

2 years ago