System A has ONE real solution
System B has NO real solutions
System C has ONE real solution
Answer:
4 is the median to your problem
Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
<u>Answer</u>
The first student was right.
The length of the long side is at least 13 inches.
<u>Explanation</u>
The perimeter of any figure is the distance all round.
Perimeter of a rectangle = 2(l+w). Where l is length and w is the width.
2(l + w) ≥ 30
2{(x-3) + 2} ≥ 30
2(x-3+2) = 30
2(x - 1) ≥ 30
x - 1 ≥ 15
x ≥ 16
When x = 16,
l = 16-3
= 13 inches
The length of the long side is 13 inches. The first student was right.
