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jonny [76]
2 years ago
12

In the morning, a cow produced 2 3 5 liters of milk, and in the evening it produced 3 3 10 liters more than in the morning. How

many liters were milked during that day?
URGENT URGENT URGENT URGENT URGENT
Mathematics
2 answers:
love history [14]2 years ago
6 0

Answer:its 8 1/2

Step-by-step explanation: you add 3 3/10 and 2 3/5 then add 2 3/5 again and you get 8 1/2

polet [3.4K]2 years ago
5 0

Answer:

8 1/2 liters

Step-by-step explanation:

In the morning the cow produced 2 3/5 liters of milk.

In the evening, the cow produced 3 3/10 more than in the morning; this means to find the total amount produced in the evening we add

2 3/5 + 3 3/10

To add these, find a common denominator; the first thing 5 and 10 will both go into is 10.  It takes two 5's to make 10; this means we use two 3's on the numerator, which gives us 2 6/10.

The second fraction is already over 10, so we do not need to change it.

2 6/10 + 3 3/10

Add the whole numbers, then add the numerators; this gives us 5 9/10.  The cow produces 5 9/10 liters in the evening.

To find the total amount produced that day, add this number to the amount in the morning:

5 9/10 + 2 3/5

The common denominator is 10 again.  Changing 2 3/5 to tenths is still 2 6/10:

5 9/10 + 2 6/10 = 7 15/10

15/10 is improper.  10 will go into 15 one time; this is the whole number.  We add this to 7, giving us 8.  This leaves us with 15-10=5 for the numerator:

8 5/10

This simplifies to 8 1/2.

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6 0
3 years ago
Differentiate the function. f(x) = sin(9 ln(x))
gayaneshka [121]

Answer: f'(x)=\dfrac{9\cos(9\ln (x))}{x}.

Step-by-step explanation:

The given function is

f(x)=\sin(9\ln (x))

Using chain rule differentiate w.r.t. x.

f'(x)=\cos(9\ln (x))\dfrac{d}{dx}(9\ln (x))      \left[\because \dfrac{d}{dx}\sin x=\cos x\right]

f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]

f'(x)=\cos(9\ln (x))\left[9\times \dfrac{1}{x}\right]       \left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]

f'(x)=\dfrac{9\cos(9\ln (x))}{x}

Therefore, f'(x)=\dfrac{9\cos(9\ln (x))}{x}.

5 0
3 years ago
ASAP ASAP ASAP asap help me​
Nataly [62]

Answer:

16

Step-by-step explanation:

We can use the Pythagorean theorem to find the  height

a^2 + b^2 = c^2 with a and b legs and c the hypotenuse

The triangle is a right triangle with legs GH and FG and hypotenuse FH

FG^2 + GH^2 = FH^2

FG ^2 + 12^2 = 20^2

FG^2 +144 = 400

Subtract 144 from each side

FG^2 +144-144 = 400-144

FG^2 =256

Take the square root of each side

sqrt(FG^2) =sqrt(256)

FG = 16

7 0
3 years ago
Read 2 more answers
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