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tekilochka [14]
3 years ago
15

1. If temperature is increased, the number of collisions per second do what

Chemistry
1 answer:
GaryK [48]3 years ago
7 0
Increase..................
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What is the charge of a particle having nine protons and 10 electrons?
KIM [24]

Answer:

the charge is negative

8 0
3 years ago
How many grams of calcium hydroxide is produced from 9.4 g of calcium chloride in this balanced
Yuliya22 [10]

Answer:

6.27 [gr].

Explanation:

the required mass can be calculated as:

m[Ca(OH)₂]=M[Ca(OH)₂]*m[CaCl₂]/M[CaCl₂], where M - molar mass [gr/mol], m - mass [gr];

m[Ca(OH)₂]=9.4*74/111≈6.2(6) [gr].

7 0
1 year ago
An element has atomic number 10 and an atomic mass of 20. How many neutrons are in the atom of this element?
Igoryamba

The answer is A. 10.

3 0
3 years ago
What is ΔE in kJ for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same t
kenny6666 [7]

Answer: 20.7 kJ

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system=-P\Delta V  {Work is done on the system is positive as the final volume is lesser than initial volume}

w = 4.51 kcal = 4.51\times 4.184kJ=18.9kJ    (1kcal = 4.184kJ)

q = +1.79 kJ   {Heat absorbed by the system is positive}

\Delta E=+1.79+(18.9)=20.7kJ

Thus \Delta E for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same time is 20.7 kJ

4 0
3 years ago
The time necessary for the decay of one- half sample of a radioactive substance is a _____. mass defect daughter half life nucli
Mazyrski [523]

Answer: half life

Explanation: Radioactive decay follows first order kinetics and the time required for the decay of a radioactive material is calculated as follows:

t=\frac{2.303}{k}\hspace{1mm}log\frac{x}{a}

t= time required

k= disintegration constant

x= amount of substance left after time t

a= initial amount of substance

when one half of the sample is decayed, one half of the sample remains and t can be represented as t_{1/2}

at t= t_{1/2}, x=\frac{a}{2}

t_{1/2}=\frac{2.303}{k}\hspace{1mm}log\frac{a/2}{a}

t_{1/2}=\frac{0.693}{k}

3 0
3 years ago
Read 2 more answers
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