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tekilochka [14]
4 years ago
15

1. If temperature is increased, the number of collisions per second do what

Chemistry
1 answer:
GaryK [48]4 years ago
7 0
Increase..................
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Please help fast, I will give brainliest.
frez [133]

Answer:

The reaction is favorable at all temperatures

Explanation:

Since G = H - TS, -H and +S would result in G = -H -TS, which will always be negative.

7 0
3 years ago
The heat of fusion AH, of ethyl acetate (C4H802) is 10.5 kinol. Calculate the change in entropy as when 398. g of ethy, acetate
Hitman42 [59]

<u>Answer:</u> The entropy change of the ethyl acetate is 133. J/K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ethyl acetate = 398 g

Molar mass of ethyl acetate = 88.11 g/mol

Putting values in above equation, we get:

\text{Moles of ethyl acetate}=\frac{398g}{88.11g/mol}=4.52mol

To calculate the entropy change for different phase at same temperature, we use the equation:

\Delta S=n\times \frac{\Delta H_{fusion}}{T}

where,  

\Delta S = Entropy change  = ?

n = moles of ethyl acetate = 4.52 moles

\Delta H_{fusion} = enthalpy of fusion = 10.5 kJ/mol = 10500 J/mol   (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = 84.0^oC=[84+273]K=357K

Putting values in above equation, we get:

\Delta S=\frac{4.52mol\times 10500J/mol}{357K}\\\\\Delta S=132.9J/K

Hence, the entropy change of the ethyl acetate is 133. J/K

7 0
3 years ago
How to test for carbon dioxide ​
Kaylis [27]

Answer:  carbon dioxide detector

6 0
3 years ago
Read 2 more answers
Please Help Me!
avanturin [10]

Answer:

B) Cu(s) is metal that reacts spontaneously with NiCl2(aq).

4 0
3 years ago
Read 2 more answers
A student wants to dissolve the maximum amount of CaF2 (Ksp = 3.2 x 10^−11) to make 1 L of aqueous solution.
Mekhanik [1.2K]

Answer:

The answer to A would be iv) 0.01 M HCL, but I'm not sure what the answer to part B is. Hope this helps.

Explanation:

7 0
3 years ago
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