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Grace [21]
1 year ago
10

When used as pure gases for welding ferrous metals, ____ may produce an erratic arc action, promote undercutting, and result in

other flaws.
Chemistry
1 answer:
kvv77 [185]1 year ago
4 0

Answer:

argon and helium

Explanation:

Argon and Helium is belongs to noble gas. Since novel gases are completely filled outer orbital. therefore they are erratic nature. Hence, noble gas are very stable as it neither except electron nor it denote due to it paired of electronic configuration.

Depending on the materials being welded, these atmospheric gases react with welding area and either it reduces the quality of the weld or make the welding more difficult.

Therefore, to protect welding area from atmospheric gases noble gases which are small in size are used.

Thus, argon and helium are used.

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Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re
laiz [17]

Answer:

80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.

Explanation:

From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.

6 0
3 years ago
If the half-life of a radioactive substances is 590 million years and you have 40 atoms of it, how many half-lives will have pas
Nady [450]

Answer:

3

Explanation:

Applying,

2^{n'} = R/R'............... Equation 1

Where n' = number of halflives that have passed, R = Original atom of the substance, R' = atom of the substance left after decay.

From the question,

Given: R = 40 atoms, R' = 5 atoms

Substitute these values into equation 1

2^{n'} = 40/5

2^{n'} = 8

2^{n'} = 2³

Equation the base,

n' = 3

3 0
3 years ago
One gram of salt in 100 liters of water could be considered a _______________________ solution. A) concentrated B) dilute C) sat
vitfil [10]

Answer:I believe your answer would be option B) dilute. Hope this helps.

Explanation:

3 0
3 years ago
Read 2 more answers
What is the volume of 88.2 g of silver metal (density = 10.50 g/cm^3)
babymother [125]

Answer:

The answer is

<h2>8.4 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}

From the question

mass = 88.2 g

density = 10.5 g/cm³

The volume is

volume =  \frac{88.2}{10.5}

We have the final answer as

<h3>8.4 mL</h3>

Hope this helps you

8 0
3 years ago
Read 2 more answers
What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?
spayn [35]

We know that [OH⁻] * [H⁺] = 10⁻¹⁴

plugging the value of [H⁺]

[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ * (10³/1.2)

[OH⁻] = 833.3 * 10⁻¹⁴

[OH⁻] = 8.33 * 10⁻¹²

7 0
3 years ago
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