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Grace [21]
1 year ago
10

When used as pure gases for welding ferrous metals, ____ may produce an erratic arc action, promote undercutting, and result in

other flaws.
Chemistry
1 answer:
kvv77 [185]1 year ago
4 0

Answer:

argon and helium

Explanation:

Argon and Helium is belongs to noble gas. Since novel gases are completely filled outer orbital. therefore they are erratic nature. Hence, noble gas are very stable as it neither except electron nor it denote due to it paired of electronic configuration.

Depending on the materials being welded, these atmospheric gases react with welding area and either it reduces the quality of the weld or make the welding more difficult.

Therefore, to protect welding area from atmospheric gases noble gases which are small in size are used.

Thus, argon and helium are used.

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Boyle's Law represents the relationship of volume as pressure changes. The constants of Boyle's Law are:
Aleksandr [31]

Answer:

d. Temperature and number of molecules of gas  

Step-by-step explanation:

Boyle's Law states, "The volume of a fixed mass of a gas is inversely proportional to the pressure if the temperature remains constant."

Let's examine the words.

"… volume…is inversely proportional to the pressure …" This means that volume and pressure are the <em>variables</em>.

"… fixed mass of a gas …" means that the number of molecules is constant.

"… temperature remains constant" speaks for itself.

a, c, and e are <em>wrong</em>, because pressure is a variable.

b is <em>wrong</em>, because volume is a variable.

5 0
3 years ago
The equilibrium constant Kp for the reaction (CH3),CCI (g) = (CH3),C=CH, (g) + HCl (g) is 3.45 at 500. K. (5.00 x 10K) Calculate
Karolina [17]

<u>Answer:</u> The value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

<u>Explanation:</u>

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

K_p = equilibrium constant in terms of partial pressure = 3.45

K_c = equilibrium constant in terms of concentration = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 500 K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-1=1

Putting values in above equation, we get:

3.45=K_c\times (0.0821\times 500)^{1}\\\\K_c=\frac{3.45}{0.0821\times 500}=0.084

The equation used to calculate concentration of a solution is:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}

Initial moles of (CH_3)_3CCl(g) = 1.00 mol

Volume of the flask = 5.00 L

So, \text{Concentration of }(CH_3)_3CCl=\frac{1.00mol}{5.00L}=0.2M

For the given chemical reaction:

                (CH_3)_3CCl(g)\rightarrow (CH_3)_2C=CH(g)+HCl(g)

Initial:               0.2                    -                        -

At Eqllm:          0.2 - x               x                       x

The expression of K_c for above reaction follows:

K_c=\frac{[(CH_3)_2C=CH]\times [HCl]}{[(CH_3)_3CCl]}

Putting values in above equation, we get:

0.084=\frac{x\times x}{0.2-x}\\\\x^2+0.084x-0.0168=0\\\\x=0.094,-0.178

Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration

Calculating the concentration of reactants and products:

[(CH_3)_2C=CH]=x=0.094M

[HCl]=x=0.094M

[(CH_3)_3CCl]=(0.2-x)=(0.2-0.094)=0.106M

Hence, the value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

8 0
3 years ago
What element is a non-metal.<br> A. Mg<br> B. Rb<br> C. Li<br> D. Br<br> E. Si
Goryan [66]

Answer:

D.) Br

Explanation:

I don’t really have an explanation.

I hope this helps!

4 0
3 years ago
Read 2 more answers
If more solute can be dissolved in a solvent, the solution is
WARRIOR [948]

Answer:

the answer is unsaturated

Explanation:

A saturated solution contains more solute per volume of solvent than an unsaturated solution. The solute has dissolved until no more can, leaving undissolved matter in the solution. ... In a supersaturated solution, there is more dissolved solute than in a saturated solution.

7 0
3 years ago
A mixture of chalk powder and water can be
grin007 [14]

Answer:

<h3>Right answer is: ( a) chalk powder remains suspended in water.</h3>

Explanation:

Filtration is the technique used to separate suspended solute particles from a solution . The chalk powder remains suspended in the solution and can easily be filtered through a filter paper , the chalk powder can be collected on the filter paper and clear solvent is collected as the filtrate.

4 0
3 years ago
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