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Dvinal [7]
3 years ago
12

A__ has a regular polygon base and a vertex over the center of the base.

Mathematics
2 answers:
allochka39001 [22]3 years ago
5 0
I believe the answer is B
Nikolay [14]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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What is the difference between 3/7 and 1/14
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Hi Bamdeedaowzwbi

Lets find the LCD of both fractions which is 14

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*Key word in the question was difference, difference in math definition means subtraction.
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Step-by-step explanation:

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Step-by-step explanation:

40 -  {x}^{2}  = 0 \\  \therefore \:  {x}^{2}  = 40 \\ \therefore \: x =  \pm \sqrt{40} \\  \therefore \: x =  \pm \sqrt{4 \times 10} \\  \huge \red{ \boxed{\therefore \: x  = \pm 2\sqrt{10}}}

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7 0
3 years ago
Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D
mr_godi [17]

Answer:

\displaystyle g'(s) = (s-s^4)^6

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt  \right] = f(x)

Where <em>a</em> is some constant.

We can let:
\displaystyle g(t) = (t-t^4)^6

By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]

Hence, by the Fundamental Theorem:

\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\  & = (s-s^4)^6\end{aligned}

3 0
2 years ago
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