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Tju [1.3M]
2 years ago
6

Give reasons. a.Steel is an alloy. b.Sodium is a metal.

Chemistry
1 answer:
JulsSmile [24]2 years ago
4 0

Answer:

  1. <em>stee</em><em>l</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>allo</em><em>y</em><em> </em><em>because</em><em> </em><em>steel</em><em> </em><em>when</em><em> </em><em>oth</em><em>er</em><em> </em><em>ele</em><em>ments</em><em> </em><em>compri</em><em>sing</em><em> </em><em>metals</em><em> </em><em>and</em><em> </em><em>n</em><em>o</em><em>n</em><em>metals</em><em> </em><em>a</em><em>re</em><em> </em><em>adde</em><em>d</em><em> </em><em>to</em><em> </em><em>Carbon</em><em> </em><em>ste</em><em>el</em><em> </em><em>,</em><em> alloy</em><em> </em><em>ste</em><em>el</em><em> </em><em>is</em><em> </em><em>for</em><em>med</em><em>.</em>
  2. <em>Sodi</em><em>um</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>meta</em><em>l</em><em> </em><em>beca</em><em>use</em><em> </em><em>it</em><em> </em><em>i</em><em>s</em><em> </em><em>hi</em><em>ghly</em><em> </em><em>reactive</em><em> </em><em>metal</em><em>.</em><em>i</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>the</em><em> </em><em>memb</em><em>er</em><em> </em><em>of</em><em> </em><em>alkali</em><em> </em><em>me</em><em>tal</em><em> </em><em>fami</em><em>ly</em><em> </em><em>abo</em><em>ut</em><em> </em><em>the</em><em> </em><em>perio</em><em>dic</em><em> </em><em>table</em><em> </em><em>.</em><em>it</em><em> </em><em>has</em><em> </em><em>one</em><em> </em><em>electron</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>outer</em><em>most</em><em> </em><em>electron</em><em> </em><em>shel</em><em>l</em><em>.</em>

Explanation:

Hope it's help !

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Answer:

1.Reaction rate is how fast a chemical reaction proceeds.

2.Nature of the reaction, Pressure factor

, Solvent, Catalyst and inhibitors.

3.Physical change is a temporary change. A chemical change is a permanent change. A Physical change affects only physical properties i.e. shape, size, etc.

4. One example of the effect of temperature is the use of lightsticks or glowsticks.

5.When the particle size of a fixed mass of a solid reactant becomes smaller, the total exposed surface area becomes larger, the rate of reaction increases. an example could be ice and water when the atoms are stuck together a solid but all over the place as a liquid.

6. Sometimes a reaction depends on catalysts to do their job. In that case, changing the concentration of the catalyst can speed up or slow down the reaction. For example, enzymes speed up biological reactions, and their concentration affects the rate of reaction.

7.A catalyst is a chemical substance that affects the rate of a chemical reaction by altering the activation energy required for the reaction to proceed. For example, a catalyst could cause a reaction between reactants to happen at a faster rate or at a lower temperature than would be possible without the catalyst.

Explanation:

I hope this helps have a great day! :)

7 0
3 years ago
Calculate the percent yield of benzyl alcohol Sue obtained when doing the following reaction. Sue started with 2.1 g of benzoic
Pachacha [2.7K]

Answer:

The percent yield is 116.6 %

Explanation:

Step 1: Data given

Mass of benzoic anhydride = 2.1 grams

Mass of sodium borohydride = 0.15 grams

Molar mass of benzoic anhydride = 226.23 g/mol

Molar mass of NaBH4 = 37.83 g/mol

Mass of benzyl alcohol produced = 0.5 grams

Step 2: The balanced equation

C14H10O3 + NaBH4 → C7H6O2 + C7H8O + NaB

Step 3: Calculate moles of C14H10O3

Moles C14H10O3 = Mass / molar mass

Moles C14H10O3 = 2.10 grams / 226.23 g/mol

Moles C14H10O3 = 0.00928 moles

Step 4: Calculate moles NaBH4

Moles NaBH4 = 0.150 grams / 37.83 g/mol

Moles NaBH4 = 0.00397 moles

Step 5: Calculate limiting reactant

For 1 mol of C14H10O3 we need 1 mol of NaBH4 to produce 1 mol of C7H8O

NaBH4 is the limiting reactant. It will completely be consumed ( 0.00397 moles).

C14H10O3 is in excess. There will react 0.00397 moles.

There will remain 0.00928 - 0.00397 = 0.00531 moles

Step 6: Calculate moles of C7H8O

For 1 mol of C14H10O3 we need 1 mol of NaBH4 to produce 1 mol of C7H8O

For 0.00397 of C14H10O3 we need 0.00397 mol of NaBH4 to produce 0.00397 mol of C7H8O

Step 7: Calculate mass of C7H8O

Mass of C7H8O = Moles * molar mass

Mass of C7H8O = 0.00397 moles * 108.14 g/mol

Mass of C7H8O = 0.429 grams = theoretical yield

Step 8: Calculate % yield

% yield = (actual yield/ theoretical yield) * 100%

% yield = 0.5/0.429) *100 %

% yield = 116.6 %

The percent yield is 116.6 %

3 0
3 years ago
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