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Tju [1.3M]
2 years ago
6

Give reasons. a.Steel is an alloy. b.Sodium is a metal.

Chemistry
1 answer:
JulsSmile [24]2 years ago
4 0

Answer:

  1. <em>stee</em><em>l</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>allo</em><em>y</em><em> </em><em>because</em><em> </em><em>steel</em><em> </em><em>when</em><em> </em><em>oth</em><em>er</em><em> </em><em>ele</em><em>ments</em><em> </em><em>compri</em><em>sing</em><em> </em><em>metals</em><em> </em><em>and</em><em> </em><em>n</em><em>o</em><em>n</em><em>metals</em><em> </em><em>a</em><em>re</em><em> </em><em>adde</em><em>d</em><em> </em><em>to</em><em> </em><em>Carbon</em><em> </em><em>ste</em><em>el</em><em> </em><em>,</em><em> alloy</em><em> </em><em>ste</em><em>el</em><em> </em><em>is</em><em> </em><em>for</em><em>med</em><em>.</em>
  2. <em>Sodi</em><em>um</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>meta</em><em>l</em><em> </em><em>beca</em><em>use</em><em> </em><em>it</em><em> </em><em>i</em><em>s</em><em> </em><em>hi</em><em>ghly</em><em> </em><em>reactive</em><em> </em><em>metal</em><em>.</em><em>i</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>the</em><em> </em><em>memb</em><em>er</em><em> </em><em>of</em><em> </em><em>alkali</em><em> </em><em>me</em><em>tal</em><em> </em><em>fami</em><em>ly</em><em> </em><em>abo</em><em>ut</em><em> </em><em>the</em><em> </em><em>perio</em><em>dic</em><em> </em><em>table</em><em> </em><em>.</em><em>it</em><em> </em><em>has</em><em> </em><em>one</em><em> </em><em>electron</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>outer</em><em>most</em><em> </em><em>electron</em><em> </em><em>shel</em><em>l</em><em>.</em>

Explanation:

Hope it's help !

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The product gas is then passed through a concentrated solution of KOH to remove the CO2. After passage through the KOH solution,
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<u>Answer:</u> The mass percent of nitrogen gas in the compound is 13.3 %

<u>Explanation:</u>

Assuming the chemical equation of the compound forming product gases is:

\text{Compound}\xrightarrow[CuO(s)]{Hot}N_2(g)+CO_2(g)+H_2O(g)

Now, the product gases are treated with KOH to remove carbon dioxide.

We are given:

p_{Total}=726torr\\P_{water}=23.8torr\\

So, pressure of nitrogen gas will be = p_{Total}-p_{water}=726-23.8=702.2torr

To calculate the number of moles of nitrogen, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of nitrogen gas = 702.2 torr = 0.924 atm    (Conversion factor: 1 atm = 760 torr)

V = Volume of nitrogen gas = 31.8 mL = 0.0318 L   (Conversion factor:  1 L = 1000 mL)

T = Temperature of nitrogen gas = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

0.924atm\times 0.0318L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\n_{mix}=\frac{0.924\times 0.0318}{0.0821\times 298}=0.0012mol

  • To calculate the mass of nitrogen gas, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.0012 moles

Putting values in above equation, we get:

0.0012mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.0012mol\times 28g/mol)=0.0336g

  • To calculate the mass percent of nitrogen gas in compound, we use the equation:

\text{Mass percent of nitrogen gas}=\frac{\text{Mass of nitrogen gas}}{\text{Mass of compound}}\times 100

Mass of compound = 0.253 g

Mass of nitrogen gas = 0.0336 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{0.0336g}{0.253g}\times 100=13.3\%

Hence, the mass percent of nitrogen gas in the compound is 13.3 %

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How many moles are in 91.5 grams of Helium?
konstantin123 [22]

In order to find the number of moles with a given mass of Helium, we need to use its molar mass, which is 4.0026g/mol, therefore we will have:

4.0026g = 1 mol of Helium

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Write the Henderson-Hasselbalch equation for a propanoic acid solution ( CH3CH2CO2H , pKa=4.874 ) using the symbols HA and A− ,
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Answer:

a) [A⁻]/[HA] = 0.227

b) [A⁻]/[HA] = 0.991

c) [A⁻]/[HA] = 2.667

Explanation:

In the Henderson-Hasselbalch equation, HA stands from an acid an A⁻ stands from its conjugate base, as follows:

  • CH₃CH₂CO₂H = HA
  • CH₃CH₂CO₂⁻ = A⁻

pH = pka + Log [A⁻]/[HA]

pH = 4.874 + Log[CH₃CH₂CO₂⁻]/[CH₃CH₂CO₂H]

  • (a)

4.23 = 4.874 + Log [A⁻]/[HA]

-0.644 = Log [A⁻]/[HA]

10^{-0.644} = [A⁻]/[HA]

0.227 = [A⁻]/[HA]

  • (b)

4.87 = 4.874 + Log [A⁻]/[HA]

-0.004 = Log [A⁻]/[HA]

10^{-0.004} = [A⁻]/[HA]

0.991 = [A⁻]/[HA]

  • (c)

5.30 = 4.874 + Log [A⁻]/[HA]

0.426 = Log [A⁻]/[HA]

10^{0.426} = [A⁻]/[HA]

2.667 = [A⁻]/[HA]

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