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Tju [1.3M]
3 years ago
6

Give reasons. a.Steel is an alloy. b.Sodium is a metal.

Chemistry
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

  1. <em>stee</em><em>l</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>allo</em><em>y</em><em> </em><em>because</em><em> </em><em>steel</em><em> </em><em>when</em><em> </em><em>oth</em><em>er</em><em> </em><em>ele</em><em>ments</em><em> </em><em>compri</em><em>sing</em><em> </em><em>metals</em><em> </em><em>and</em><em> </em><em>n</em><em>o</em><em>n</em><em>metals</em><em> </em><em>a</em><em>re</em><em> </em><em>adde</em><em>d</em><em> </em><em>to</em><em> </em><em>Carbon</em><em> </em><em>ste</em><em>el</em><em> </em><em>,</em><em> alloy</em><em> </em><em>ste</em><em>el</em><em> </em><em>is</em><em> </em><em>for</em><em>med</em><em>.</em>
  2. <em>Sodi</em><em>um</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>meta</em><em>l</em><em> </em><em>beca</em><em>use</em><em> </em><em>it</em><em> </em><em>i</em><em>s</em><em> </em><em>hi</em><em>ghly</em><em> </em><em>reactive</em><em> </em><em>metal</em><em>.</em><em>i</em><em>t</em><em> </em><em>i</em><em>s</em><em> </em><em>the</em><em> </em><em>memb</em><em>er</em><em> </em><em>of</em><em> </em><em>alkali</em><em> </em><em>me</em><em>tal</em><em> </em><em>fami</em><em>ly</em><em> </em><em>abo</em><em>ut</em><em> </em><em>the</em><em> </em><em>perio</em><em>dic</em><em> </em><em>table</em><em> </em><em>.</em><em>it</em><em> </em><em>has</em><em> </em><em>one</em><em> </em><em>electron</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>outer</em><em>most</em><em> </em><em>electron</em><em> </em><em>shel</em><em>l</em><em>.</em>

Explanation:

Hope it's help !

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How many moles of helium are 8.84×10^24 atoms of He?
viva [34]

Answer:

14.77 mol.

Explanation:

  • It is known that every 1.0 mole of compound or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

<u><em>Using cross multiplication:</em></u>

1.0 mole of He contains → 6.022 x 10²³ atoms.

??? mole of He contains → 8.84 x 10²⁴ atoms.

<em>∴ The no. of moles of He contains (8.84 x 10²⁴ atoms) </em>= (1.0 mol)(8.84 x 10²⁴ atoms)/(6.022 x 10²³ atoms) =<em> 14.77 mol.</em>

8 0
3 years ago
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erma4kov [3.2K]

In the so called rain shadow effect we have interaction between all of the four major Earth spheres. When we have a coastal region where there's a high mountain range, the part of the mountain that is facing the sea will differ a lot from the part of the mountain that is on the other side. The water from the sea evaporates. The water vapor makes the air wet. The warm and wet air masses from the sea will come to the coastline, once they reach the mountain they will start to accumulate as they can not pass through it. As they accumulate rainfall appears. The rainfall contributes to a lush vegetation on this side of the mountain (windward side). The rain shadow effect appears on the leeward side of the mountain, and it mostly gets dry, strong, downward winds. These conditions result in drier climate, much less vegetation, and much increased erosion. Thus we can easily see that we have in this case interaction between the hydrosphere (the sea and the rainfall), the geosphere (the ground, soil, rocks), biosphere (the vegetation), and atmosphere (the winds, the clouds).

6 0
4 years ago
The following reaction shows the products when sulfuric acid and aluminum hydroxide react.
Elden [556K]

The correct answer is approximately 11.73 grams of sulfuric acid.

The theoretical yield of water from Al(OH)3 is lower than that of H₂SO₄. As a consequence, Al(OH)3 is the limiting reactant, H₂SO₄ is in excess.

The balanced equation is:

2Al(OH)₃ + 3H₂SO₄ ⇒ Al₂(SO₄)₃ + 6H₂O

Each mole of Al(OH)3 corresponds to 3/2 moles of H₂SO₄. The molecular mass of Al(OH)3 is 78.003 g/mol. There are 15/78.003 = 0.19230 moles of Al(OH)3 in the five grams of Al(OH)3 available. Al(OH)3 is in limiting, which means that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.

The molar mass of H₂SO₄ is 98.706 g/mol. The mass of 0.28845 moles of H₂SO₄ is 0.28845 × 98.706 = 28.289 g

40 grams of sulfuric acid is available, out of which 28.289 grams is consumed. The remaining 40-28.289 = 11.711 g is in excess, which is closest to the first option, that is, 11.73 grams of H₂SO₄.

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