Answer:
33 N
Explanation:
v = Velocity of fluid = 8+2 = 10 m/s
= Density of fluid = 1.2 kg/m³
C = Coefficient of drag = 1.1
A = Cross sectional area = 0.5 m²
Drag force is given by
The drag force on the athlete is 33 N
Answer:
Explanation:
The work increased the potential energy
W = PE = mgh = 40(9.8)(15) = 5880 J(oules)
Answer:
<h2>1 st statement is correct </h2>
Explanation:
The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside
<h2>hope you understand and got your answer by my explanation </h2><h2>thanks </h2>
<h2>please give brainliest plz follow </h2>
you are so wise how do you do it?
Answer:
Ep = 0.6095 [J]
Explanation:
As defined in the problem statement, potential energy is defined as the product of mass by gravity by height. But first we must convert all the values given to measures of the international system (SI)
g = gravity = 10 [m/s^2]
h = elevation = 40 [ft] = 12.19 [m]
m = mass = 5 [g] = 0.005 [kg]
Ep = potential energy [J]
Ep = 0.005*10*12.19 = 0.6095 [J]
