Answer:
c = 4
Explanation:
From work-energy theorem KE = workdone.
Given F = (cx - 3.00x²)i
W = ∫Fdx = ∫(cx - 3.00x²)dx = cx²/2 –3.00x³/3 + A
W = cx²/2 –x³ + A
Where A is a constant
At x = 0, KE = 20J
So W = 20J at x = 0
20 = c×0 - 0 +A
A = 20
So W = cx²/2 –x³ + 20
Also when x = 3.00m, W = KE = 11J
So
11 = c×3²/2 – 3³ + 20
11 = 4.5c – 7
4.5c = 11 + 7
4.5c = 18
c = 18/4.5 = 4
c = 4
Answer:
See the explanation below
Explanation:
In the attached image we can see the free body diagram and forces acting on the book.
Force F, which acts to the right, the friction force which acts in the opposite direction to the movement, i.e. to the left.
The force exerted by the weight of the book that is equal to the product of the mass of the book by the gravity of the book. The normal force that is equal in magnitude to the weight of the book but in the opposite direction.
Distance between the focal point and the center of the lens
<span>Stainless steel is a metal alloy
that made up mainly of carbon and chromium. In combination
with low carbon contents, chromium is highly reactive element that imparts
remarkable resistance to corrosion and heat.</span>
Moreover, stainless
steel is mixed up with sufficient nickel, which is an essential allying element
in the series of stainless steel grades. Other components are manganese,
molybdenum, silicon, titanium, aluminum, niobium, copper, nitrogen, and sulfur.
ANSWER:
F(h)= 230 N is the horizontal force you will need to move the pickup along the same road at the same speed.
STEP-BY-STEP EXPLANATION:
F(h) is Horizontal Force = 200 N
V is Speed = 2.4 m/s
The total weight increase by 42%
coefficient of rolling friction decrease by 19%
Since the velocity is constant so acceleration is zero; a=0
Now the horizontal force required to move the pickup is equal to the frictional force.
F(h) = F(f)
F(h) = mg* u
m is mass
g is gravitational acceleration = 9.8 m/s^2
200 = mg*u
Since weight increases by 42% and friction coefficient decreases by 19%
New weight = 1+0.42 = 1.42 = (1.42*m*g)
New friction coefficient = μ = 1 - 0.19 = 0.81 = 0.81 u
F(h) = (0.81μ) (1.42 m g)
= (0.81) (1.42) (μ m g)
= (0.81) (1.42) (200)
= 230 N
