Question

A chemistry student needs 60.00 g of butanoic acid for an experiment. He has available 120. g of a 36.9% w/w solution of butanoic acid in ethanol. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

Answer 1

Answer:

No solution

Explanation:

36.9% w/w solution of butanoic acid in ethanol means 36.9 grams of butanoic acid per 100 grams of solution. The amount of butanoic acid in 120.0 g of the solution may be calculated:

(120.0 g solution)(36.9 g butanoic acid / 100 g solution) = 44.3 g butanoic acid.

There is not sufficient butanoic acid for the experiment.

Answer 2

Answer: There is no solution for the required amount of butanoic acid.

Explanation:

We are given:

Mass of butanoic acid needed = 60.00 grams

36.9 % w/w butanoic acid solution

This means that 36.9 grams of butanoic acid is present in 100 grams of solution

Applying unitary method:

If 36.9 grams of butanoic acid is present in 100 grams of solution

So, 60.00 grams of butanoic acid will be present in = $\frac{100}{36.9}\times 60.00=162.6g$

As, the given amount of solution is less than the required amount.

Hence, there is no solution for the required amount of butanoic acid.