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2 years ago

Potassium and bromine draw the charges swapping charges formula and name

Chemistry

1 answer:

Elis [28]2 years ago

8 0

Answer:

I'm not really sure if you're interested in the electron dot diagram of the potassium and bromine atoms, or of potassium bromide,

KBr, so I'll show you both. You can use this example to find the electron dot diagram of hydrogen bromide, HBr.

Explanation:

You might be interested in

The fluid in a barometer (shown above) is mercury, Hg. Why point

PIT_PIT [208]

Answer:

Mercury responds to temperatures differently than water. When mercury is cold, the molecules bunch together, making it seem to be less liquid, and the opposite happens during heat.

Hope this helps!

5 0

2 years ago

Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h

bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

We know that,

The relation between the $C_p\text{ and }C_v$ for an ideal gas are :

$C_p-C_v=R$

As we are given :

$C_p=28.253J/K.mole$

$28.253J/K.mole-C_v=8.314J/K.mole$

$C_v=19.939J/K.mole$

Now we have to calculate the entropy change of the gas.

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

$\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J$

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. $(w=-pdV)$

(C) Heat during the process will be,

$q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J$

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0

3 years ago

6. if a cross country runner travels at a speed of 10 mph and he runs for 2 hours, how many miles will he have run at the end of

storchak [24]

Explanation:

distance = speed x time

distance = 10 x 2

distance = 20miles

hope that helps :)

5 0

2 years ago

Jati has a sample of a solid.Suggest how he could find out weather the solid is a pure substance or a mixture of substances?

Vsevolod [243]

Answer:

The melting point range of a substance is the temperature range from which the first crystal starts to melt, to the temperature at which the last crystal finishes melting. An impure substance is a type of mixture, so melting points can be used to find out if a substance is pure or impure.

pls mark brainiest

Explanation:

5 0

2 years ago

What is the vapor pressure of CS2CS2 in mmHgmmHg at 26.5 ∘C∘C? Carbon disulfide, CS2CS2, has PvapPvap = 100 mmHgmmHg at −−5.1 ∘C

Digiron [165]

Answer: 26.5 mm Hg

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

$ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})$