The answer is 22 degrees. Law of conservation of energy stipulates that energy cannot be created or destroyed but can be transferred and also transformed from one form to another. The movement of the container, mechanical energy, was transferred to the water, as heat energy, and therefore raised the water temperatures slightly.
Answer:
When you build up a soapy lather, the molecules help lift the dirt, oil and germs from your skin
Explanation:
Soap molecules have one end that bonds with water and the other end that bonds with oils and fats .
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Answer:
Percent yield = 85.4%
Explanation:
Given data:
Mass of Al = 2.5 g
Mass of oxygen = 2.5 g
Mass of aluminium oxide = 3.5 g
Percent yield = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
First of all we will calculate the number of moles of each reactant.
Number of moles of Al:
Number of moles = mass/ molar mass
Number of moles = 2.5 g/ 27 g/mol
Number of moles = 0.09 mol
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 2.5 g/ 32 g/mol
Number of moles = 0.08 mol
Now we will compare the moles of aluminium oxide with oxygen and aluminium.
Al : Al₂O₃
4 : 2
0.09 : 2/4×0.09 = 0.045
O₂ : Al₂O₃
3 : 2
0.08 : 2/4×0.08 = 0.04
The number of moles of aluminium oxide produced by oxygen are less so it will limiting reactant.
Theoretical yield of aluminium oxide:
Mass = number of moles × molar mass
Mass = 0.04 mol × 101.96 g/mol
Mass = 4.1 g
Percent yield:
Percent yield = actual yield /theoretical yield × 100
Percent yield = 3.5 g/ 4.1 g × 100
Percent yield = 85.4%
Answer : The value of 'R' is 
Solution : Given,
At STP conditions,
Pressure = 1 atm
Temperature = 273 K
Number of moles = 1 mole
Volume = 22.4 L
Formula used : 
where,
R = Gas constant
P = pressure of gas
T = temperature of gas
V = volume of gas
n = number of moles of gas
Now put all the given values in this formula, we get the values of 'R'.
Therefore, the value of 'R' is .
It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.
If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:
360 g : 1 L = x g : 30 mL
Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 30 mL
Now, crossing the products:
x </span>· 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000
x = 10.8 g
So, from 30 mL mixture, 10.8 g of NaCl could be extracted.
Let's calculate the same for 10 mL water instead of 30 mL.
360 g : 1 L = x g : 10 mL
Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = <span>x g : 10 mL
Now, crossing the products:
x </span>· 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000
<span>x = 3.6 g
</span>
<span>So, from 10 mL mixture, 3.6 g of NaCl could be extracted.
</span>
Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and <span>from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
</span>3.6/10.8 = 1/3
Therefore, i<span>t will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water. </span>
