1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tekilochka [14]
3 years ago
9

What is the equation to determine the MA of a wedge?

Chemistry
1 answer:
inna [77]3 years ago
6 0

Answer:

length/width

Explanation:

You might be interested in
An old antacid commercial claimed that each tablet of their product could neutralize 47 times its mass in stomach acid. The acti
butalik [34]

Answer : The number of moles of HCl neutralize is, 0.00824 moles.

Explanation :

The given balanced chemical reaction is:

NaAl(OH)_2CO_3+4HCl\rightarrow NaCl+AlCl_3+3H_2O+CO_2

First we have to calculate the moles of NaAl(OH)_2CO_3

\text{Moles of }NaAl(OH)_2CO_3=\frac{\text{Mass of }NaAl(OH)_2CO_3}{\text{Molar mass of }NaAl(OH)_2CO_3}

Molar mass of NaAl(OH)_2CO_3 = 144 g/mol

\text{Moles of }NaAl(OH)_2CO_3=\frac{0.296g}{144g/mol}=0.00206mol

Now we have to calculate the moles of HCl.

From the balanced chemical reaction we conclude that,

As, 1 mole of NaAl(OH)_2CO_3 react with 4 moles of HCl

So, 0.00206 mole of NaAl(OH)_2CO_3 react with 0.00206\times 4=0.00824 moles of HCl

Thus, the number of moles of HCl neutralize is, 0.00824 moles.

8 0
3 years ago
A 18.08-g sample of the ionic compound , where is the anion of a weak acid, was dissolved in enough water to make 116.0 mL of so
Oksi-84 [34.3K]

Answer:

a) 129.14 g/mol

b) 8.87

Explanation:

Given that:

mass of the ionic compound [NaA] = 18.08 g

Volume of water = 116.0 mL = 0.116 L

Let the mole of the acid HCl = 0.140 M

Volume of the acid = 500.0 mL = 0.500 L

pH = 4.63

V_{equivalence}_{acid} = 1.00 L

Equation for the reaction can be represented as:

NaA_{(aq)} + HCl_{(aq)} -----> HA_{(aq)} + NaCl_{(aq)

From above; 1 mole of an ionic compound reacts with 1 mole of an acid to reach equivalence point = 0.140 M × 1.00 L

= 0.140 mol

Thus, 0.140 mol of HCl neutralize 0.140 mol of ionic compound at equilibrium

Thus, the molar mass of the sample = \frac{18.08g}{0.140 mole}

= 129.14 g/mol

b) since pH = pKa

Then pKa of HA = 4.63

Ka = 10^{-4.63]

= 2.3*10^{-5}

[A^-]equ = \frac{0.140M*1.00L}{1.00L+0.116L}

= \frac{0.140 mol}{1.116 L}

= 0.1255 M

K_a of HA = 2.3*10^{-5}

K_b = \frac{1.0*10^{-14}}{2.3*10^{-5}}

= 4.35*10^{-10}

                     A_{(aq)}     +     H_2O_{(l)}         \rightleftharpoons     HA_{(aq)}     +     OH^-_{(aq)}

Initial        0.1255                                            0                    0

Change     - x                                                  +  x                 + x

Equilibrium   0.1255 - x                                   x                    x

K_b = \frac{[HA][OH^-]}{[A^-]}

4.35*10^{-10} = \frac{[x][x]}{[0.1255-x]}

As K_b is very small, (o.1255 - x) = 0.1255

x = \sqrt{0.1255*4.35*10^{-10}}

[OH⁻] = x = 7.4 *10^{-6}

But pOH = - log [OH⁻]

= - log [7.4*10^{-6}]

= 5.13

pH = 14.00 = 5.13

pH = 8.87

6 0
3 years ago
if a tiny marble has a radius of 0.25mm how many marbles can be lined up across the circumference of the earth, distance of 2490
horsena [70]

Answer : The number of marbles lined up across the circumference of the earth can be, 8.013\times 10^{10} marbles

Explanation :

First we have to calculate the diameter of tiny marble.

Diameter=2\times Radius

r = radius of marble = 0.25 mm

Diameter=2\times (0.25mm)=0.50mm

Now we have to calculate the number of marbles can be lined up across the circumference of the earth.

Given:

Circumference of the earth distance = 24900mile=4.00641\times 10^{10}mm

conversion used: 1mile=1.609\times 10^6mm

Number of marbles can be lined up = \frac{4.00641\times 10^{10}mm}{0.50mm}=8.013\times 10^{10} marbles

Thus, the number of marbles lined up across the circumference of the earth can be, 8.013\times 10^{10} marbles

3 0
4 years ago
Magnesium, the element, is produced commercially by electrolysis from a molten salt (the "electrolyte") using a cell similar to
kirill115 [55]

Answer:

<u>The half-reaction that occurs on the anode of an electrolytic cell is called oxidation. </u>

This can easily be depicted by a chemical reaction as such <u>"Zn(s) = Zn2+ (aq) + (2e-)" </u>

While, the Zinc in this reaction loses two elections. Hence copper gains those electrons and becomes solid.

<em>These reactions occurring on the anode are called positive reactions. </em>

While the reaction that occurs on the cathode is called reduction. This reaction can be represented by this equation "<u>Cu2+ (aq) + 2e- = Cu(s)</u>".

<u>These non-spontaneous reactions occurring in an electrolytic cell together are called redox reactions. These generate electrical energy.</u>

7 0
3 years ago
Employers may not fire or other wise discriminate against an employee who does which of the following
Likurg_2 [28]

Answer:

race, religion, sex, if they are 40 or older, have a disability, pregnancy/childbirth. hope that helped

6 0
3 years ago
Other questions:
  • Complete the mechanism for the reaction of 2-methylbutan-2-ol in sulfuric acid
    6·1 answer
  • Liters of a 2.40 M
    15·1 answer
  • Salicylic acid (C7H6O3) reacts with acetic anhydride (C4H6O3) to form acetylsalicylic acid (C9H8O4).
    11·1 answer
  • What element are diamonds composed of
    9·2 answers
  • Help Ill give you the brainiest answer thing please just give me the right answer
    10·2 answers
  • PLISSSSS.. I NEED ANSWER NOW
    13·1 answer
  • What happens when the limiting reactant of a reaction runs out?
    15·1 answer
  • Imagine there is less gravity on Earth for
    13·1 answer
  • What are the biochemical properties of water​
    10·2 answers
  • Which element would have the greater difference between the first ionization energy and the second ionization energy
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!