Answer:
The substance that remained on the filter paper is Al(OH).
Explanation:
- Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.
- So in our experiment the product formed is aluminum hydroxide Al(OH) and sodium chloride (NaCl).
- Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.
- Hence aluminum hydroxide being only solid product remains on the filter paper.
Answer:
1.93
Explanation:
Moles of C
H
COOH = 38/1000 × 0.50 = 0.019mol
Moles of CHCOONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol
Final pH = pKa + log([CHCOONa]/[CHCOOH]
= -log Ka + log(mols of CHCOONa]/mols of CHCOOH
= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17
change in pH = final - initial pH
= 4.17 - 2.24
=1.93
Answer:
1) Dispersion forces: It is a type of force which is present between atoms and molecules. It is a weakest intermolecular force that occurs between atoms. It is also called induced dipole-induced dipole attraction.
2. Dipole-dipole: It is a type of attractive force which is present between the negative end of one molecule with the positive end of another molecule. This type of attractive force occurs between polar molecules.
3) Hydrogen bond: It is a type of electromagnetic force which is present between hydrogen and high electronegative atoms such as nitrogen and oxygen etc.
