Answer:
2637.3 litters of fluorine gas are needed to produce 879 litters of sulfur hexafluoride.
Explanation:
Given data:
Volume of SF₆ = 879 L
Pressure = 2 atm
Temperature = 273.15 k
Volume of fluorine required = ?
Solution:
Balance chemical equation:
S (s) + F₂(g) → SF₆(g)
First of all we will calculate the moles of SF₆.
PV = nRT
n = PV/RT
n = 2. atm× 879L / 0.0821 L. atm. mol⁻¹. K⁻¹ × 273.15 K
n = 1758 atm. L/ 22.43 L. atm. mol⁻¹
n = 78.4 mol
78.4 moles of SF₆ will produce.
Now we will compare the moles of SF₆ and fluorine from balance chemical equation.
SF₆ : F
1 : 3
78.4 : 3/1 × 78.4 = 235.2 moles
Now we will calculate the volume of fluorine.
PV = nRT
V = nRT / P
V= 235.2 mol. 0.0821 L. atm. mol⁻¹. K⁻¹ × 273.15 K / 2 atm
V = 5274. 5 / 2
V = 2637.3 L
2637.3 litters of fluorine gas are needed to produce 879 litters of sulfur hexafluoride.
Answer:
A resistor resists extra electric current.
Answer:
B) hyperbaric oxygen chamber to increase PO2 and clear CO from the body
Explanation:
Carbon monoxide poisoning occurs from the breathing in of poisonous gas, carbon monoxide (CO) at high levels. Large exposures of the gas can result in the loss of consciousness, seizures, or even death.
<u>Hyperbaric oxygen is used in treatment of carbon monoxide poisoning, as it hasten the dissociation of CO from carboxyhemoglobin and also cytochrome oxidase to a greater extent as compared to normal oxygen. It also enhance the oxygen transport to tissues by the plasma.</u>
For physics the answer is 47500
Answer:
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
Explanation:
Primary alcohols are stronger acids than secondary alcohols which are stronger than tertiary alcohols.
This trend is so because of the stability of the alkoxide ion formed(stabilising the base, increases the acidity). A more stabilised alkoxide ion is a weaker conjugate base (dissociation of an acid in water).
By electronic factors, When there are alkyl groups donating electrons, the density of electrons on th O- will increase a d thereby make it less stable.
By stearic factors, More alkyl group bonded to the -OH would mean the bulkier the alkoxide ion which would be harder to stabilise.
Down the group of the periodic table, basicity (metallic character) decreases as we go from F– to Cl– to Br– to I– because that negative charge is being spread out over a larger volume that is electronegativity decreases down the group.
Electronegative atoms give rise to inductive effect and a decrease in indutive effects leads to a decrease in acidity. Therefore an Increasing distance from the -OH group lsads to a decrease in acidity.
From above,
A. Methanol
B. 2-chloropropan-1-ol
C. 2,2-dichloroethanol
D. 2,2-difluoropropan-1-ol
