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3 years ago

Calculate the molarity of the solution if 80.0 g of Kool-Aid is dissolved in 1.0 L of solution.

Chemistry

1 answer:

Serga [27]3 years ago

7 0

Answer:

.234 M

Explanation:

Molarity, or concentration, of a substance is simply found by dividing the amount of that substance in moles by its volume. Here, we are given the mass (in grams) of Kool-Aid, so we need to convert that to moles. To do this, we simply need the chemical formula of Kool-Aid, which I have found to be C12H22O11. The molar mass of C12H22O11, using the periodic table, is 342.296 g. Next, take this molar mass and divide the given mass of Kool-Aid by it. You then get about .234 mol Kool-Aid.

Lastly, divide this by the volume of 1.0 L. You get .234 M as your final molarity.

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How many moles of Cs are contained in 3 moles of Cs3PO4?

Alenkinab [10]

Answer:

$\boxed {\boxed {\sf 9 \ moles \ Cs}}$

Explanation:

We are given the compound: Cs₃PO₄

According to the formula, 1 mole of cesium phosphate contains 3 moles of cesium, 1 mole of phosphate, and 4 moles of oxygen.

Therefore, there are 3 moles of cesium for 1 mole of cesium phosphate.

$\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}$

We want to calculate the moles of cesium in 3 moles of cesium phosphate, so we multiply the ratio by 3.

$3 \ mol \ Cs_3PO_4 *\frac {3 \ mol \ Cs}{1 \ mol \ Cs_3PO_4}$

$3 *\frac {3 \ mol \ Cs}{1 }= 9 \ mol \ Cs$

3 moles of cesium phosphate contains <u>9 moles of cesium.</u>

6 0

3 years ago

All atoms of an element have the same number of ________. electrons neutrons protons protons plus neutrons

Cloud [144]

Answer:

protons

Explanation:

An element, by definition, always has the same number of protons. Sodium, element 11, has 11 protons. Anything with 11 protons is a sodium atom, regardless of the number of neutrons, electrons, or politicians.

6 0

2 years ago

What is the best reason for a student to remove a dangling bracelet when heating test tubes of acidic solutions in a hot-water b

allsm [11]

So it doesnt touch and create a negative reaction

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3 years ago

Read 2 more answers

Calculate the mass of water vapour present in a room of volume 400 m3 that contains air at 27 °C on a day when the relative humi

Alex73 [517]

Answer:

Mass of water = 6251. 706g or 6.25Kg

Explanation:

Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%

Actual vapor pressure, Pw = relative humidity * saturation vapor pressure

Pw = 60% * (35.6 *0.001)atm = 0.0216atm

Note: 1mbar = 0.001atm

Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400

* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles

Note: 1m^3 = 1000dm^3,R is the molar gas constant.

Making n subject of the formula, n = PV/RT

n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles

Mass (g) = number of moles (n) * molar mass

molar mass of water=18g

Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg

6 0

3 years ago

How many moles of CaO will be produced from 23.9 g of Ca?<br>2Ca(s) + O2(g) – 20:0(3)<br>mol

inessss [21]

Answer:

0.6 moles of CaO will produced.

Explanation:

Given data:

Mass of calcium = 23.9 g

Moles of CaO produced = ?

Solution:

Chemical equation:

2Ca + O₂ → 2CaO

Number of moles of calcium:

Number of moles = mass/ molar mass

Number of moles = 23.9 g / 40 g/mol

Number of moles = 0.6 mol

Now we will compare the moles of calcium and CaO.

Ca : CaO

2 : 2

0.6 : 0.6

0.6 moles of CaO will produced.

4 0

3 years ago