All categories

3 years ago

What is net displacement vector? I just started AP Physics 1.

Physics

2 answers:

ki77a [65]3 years ago

8 0

Hey! I just started AP Physics 1 as well.

Lets break it down:

Displacement is the change in the position of a vector.

Net means total

This means that Net displacement means the addition of displacements. Also said as the "vector sum of the individual displacements".

This is all I know. Good luck!

Snowcat [4.5K]3 years ago

3 0

You have more than 1 vector. When you add them all together as vectors, the net displacement vector is a vector drawn from the arrowhead of the last vector to the non-arrowhead of the first vector. The other responder gave a good description as well. Between us, you have a pretty good definition of what a net displacement vector is.

You might be interested in

The resultant of three vectors is 90.00 cm 34o N of W. If two of these three vectors are 17.89 cm 27o W of S, and 36.00 cm NW, w

Art [367]

Answer:

Magnitude of the third vector: 57.85 cm

The direction of the third vector: 44.76 N of W

Explanation:

8 0

3 years ago

How many miles is a light year

Stells [14]

Answer:

5,878,625,370,000 miles or 5.87 Trillion miles

Explanation:

The result: One light-year equals 5,878,625,370,000 miles (9.5 trillion km).

6 0

2 years ago

Read 2 more answers

A 128 gram Radium-226 sample with a half-life of 2.25 billion years is found. How many grams will remain after two half-lives?

Bess [88]

Answer:

Option B. 32 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 128 g

Half-life (t½) = 2.25 billion years

Number of half-lives (n) = 2

Amount remaining (N) =?

The amount of 128 gram of Radium-226 that will remain after 2 half-lives has elapsed can be obtained as followb

N = 1/2ⁿ × N₀

N = 1/2² × 128

N = 1/4 × 128

N = 0.25 × 128

N = 32 g

Therefore, 32g of the sample will remain.

8 0

3 years ago

A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi

vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

$V=\frac {C_2V_2-C_1V_1}{C_1+C_2}$

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

$C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}$

Therefore

$V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437$

Charge, Q is given by CV hence for the first capacitor charge will be $Q_1=C_1V$

Here, $Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C$

8 0

3 years ago

The formula v = √2.5r models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radiu

mel-nik [20]

Answer:

The maximum safe speed of the car is 30.82 m/s.

Explanation:

It is given that,

The formula that models the maximum safe speed, v, in miles per hour, at which a car can travel on a curved road with radius of curvature r r, is in feet is given by :

$v=\sqrt{2.5\ r}$ .........(1)

A highway crew measures the radius of curvature at an exit ramp on a highway as 380 feet, r = 380 feet

Put the value of r in equation (1) as :

$v=\sqrt{2.5\ \times 380}$

v = 30.82 m/s

So, the maximum safe speed of the car is 30.82 m/s. Hence, this is the required solution.

4 0

3 years ago