By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s
Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:
mass m = 0.170 kg
initial speed u = 6 m/s.
Distance covered s = 61 m
To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V
To do this, let us first calculate the kinetic energy at which the ball move.
K.E = 1/2m
K.E = 1/2 x 0.17 x 
K.E = 3.06 J
The work done on the ball is equal to the kinetic energy. That is,
W = K.E
But work done = Force x distance
F x S = K.E
F x 61 = 3.06
F = 3.06/61
F = 0.05 N
From here, we can calculate the acceleration of the ball from Newton second law
F = ma
0.05 = 0.17a
a = 0.05/0.17
a = 0.3 m/
To calculate the final velocity, let us use third equation of motion.
= + 2as
= + 2 x 0.3 x 61
= 36 + 36
= 72
V = 
V = 8.485 m/s
Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.
Learn more about dynamics here: brainly.com/question/402617
Ideally the resistance should be ZERO
Answer:
The samples specific heat is 14.8 J/kg.K
Explanation:
Given that,
Weight = 28.4 N
Suppose, heat energy 
Temperature = 18°C
We need to calculate the samples specific heat
Using formula of specific heat
Where, m = mass
c = specific heat
= temperature
Q = heat
Put the value into the formula
Hence, The samples specific heat is 14.8 J/kg.K
Use your feet to stop it since it is soccer you can't use your hands!!!! P.S. you can't use gravity.
Answer:
The frequency of the green light is 
Explanation:
The visible region is part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of 
in the vacuum.
Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:
(1)
Where c is the speed of light, 
is the wavelength and 
is the frequency.
Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).
Then, can be isolated from equation 1
(2)
Notice that it is necessary to express the wavelength in units of meters.
⇒ 
Hence, the frequency of the green light is
