Answer:
A ) 1, 2 and 3
Explanation:
1 ) is correct because,
K donates 1 electron
F gain 1 electron from K.
If donating and gaining of electrons takes place between two electron, then type of compound formed is ionic.
2 ) is correct because,
K + F -----> KF
3 ) is correct because,
KF is soluble in cold water; very soluble in hot water.
Explanation:
A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.
The given reaction is ![^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + x^{1}_{0}n + y^{0}_{-1}\beta](https://tex.z-dn.net/?f=%5E%7B235%7D_%7B92%7DU%20%2B%20%5E%7B1%7D_%7B0%7Dn%20%5Crightarrow%20%5E%7B144%7D_%7B58%7DCe%20%2B%20%5E%7B90%7D_%7B38%7DSr%20%2B%20x%5E%7B1%7D_%7B0%7Dn%20%2B%20y%5E%7B0%7D_%7B-1%7D%5Cbeta)
Now, we balance the mass on both reactant and product side as follows.
235 + 1 =
236 = 234 + x
x = 236 -234
= 2
So, now we balance the charge on both reactant and product side as follows.
92 + 0 = ![58 + 38 + (x \times 0) + (y \times -1)](https://tex.z-dn.net/?f=58%20%2B%2038%20%2B%20%28x%20%5Ctimes%200%29%20%2B%20%28y%20%5Ctimes%20-1%29)
92 = 96 - y
y = 4
Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.
Therefore, reaction equation will be as follows.
![^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + 2^{1}_{0}n + 4^{0}_{-1}\beta](https://tex.z-dn.net/?f=%5E%7B235%7D_%7B92%7DU%20%2B%20%5E%7B1%7D_%7B0%7Dn%20%5Crightarrow%20%5E%7B144%7D_%7B58%7DCe%20%2B%20%5E%7B90%7D_%7B38%7DSr%20%2B%202%5E%7B1%7D_%7B0%7Dn%20%2B%204%5E%7B0%7D_%7B-1%7D%5Cbeta)