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3 years ago

What is the molality of a solution when 0.50 moles glucose is dissolved in 750 g of water?

Chemistry

1 answer:

xxMikexx [17]3 years ago

3 0

Answer:

0.67mol/Kg

Explanation:

The following were obtained from the question:

Mole of solute = 0.50mol

Mass of solvent = 750g = 750/1000 = 0.75Kg

Molality =?

Molality = mole of solute /mass of solvent

Molality = 0.5/0.75

Molality = 0.67mol/Kg

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In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.

mamaluj [8]

Answer:

Explanation:

We know that the

reaction catalyzing power of a catalyst ∝ surface area exposed by it

Given

volume V1= 10 cm^3

⇒ $\frac{4}{3} \pi r^3= 10$

hence r= 1.545 cm

also, surface area S1= $4\pi r^2$

now when the sphere is broken down into 8 smaller spheres

S2= 8×4πr'^2

now, equating V1 and V2 ( as the volume must remain same )

$\frac{4}{3}\pi r^3=8\times\frac{4}{3} \pi r'^3$

and solving we get

r'= r/2

therefore, S2= $8\times4\pi\frac{r}{2}^2$

S2= $2\times4\pi r^2$

S2= 2S1

hence the correct answer is

. The second run has twice the surface area.

8 0

3 years ago

A steel tank contains carbon dioxide at a pressure of 13.0 atm when the temperature is 34oC. What will be the internal gas press

morpeh [17]

Answer:

D. 15.8atm

Explanation:

Given parameters:

Initial pressure = 13atm

Initial temperature = 34°C = 34 + 273 = 307K

Final temperature = 100°C = 100 + 273 = 373K

Unknown:

Final pressure = ?

Solution:

To solve this problem, we apply a derivation of the combined gas law taking the volume as a constant.

The expression is shown mathematically below;

$\frac{P_{1} }{T_{1} }$ = $\frac{P_{2} }{T_{2} }$

P and T pressure and temperature values

1 and 2 are initial and final states

Insert the parameters and solve for T₂;

$\frac{13}{307}$ = $\frac{P_{2} }{373}$

P₂ = 15.8atm

4 0

3 years ago

4 points

Ilya [14]

The vertical columns are groups

The horizontal rows are periods

4 0

3 years ago

Read 2 more answers

Mexico City has an elevation of 7400 ft above sea level. Its normal atmospheric pressure is 589 mm Hg. At what temperature does

IRISSAK [1]

Given that the volume and amount of water are kept constant,
P/T = constant
P₁/T₁ = P₂/T₂
Normal atmospheric pressure is 746 mmHg and normal boiling point of water is 100 °C.
746/100 = 589/T₂
T₂ = 79.0 °C

5 0

3 years ago

A 16.0 mL sample of a 1.04 M potassium sulfate solution is mixed with 14.3 mL of a 0.880 M barium nitrate solution and this prec

stiks02 [169]

Number of moles in the K2SO4 sample
= (16/1000)*1.04= 0.01664 mol

Number of moles in the Ba(NO3)2 sample
= (14.3/1000*0.880)= 0.01258 mol

Since the reaction is a 1:1 ratio between the two reactants, the limiting reagent is the one containing a smaller number of moles, namely Ba(NO3)2.

The molecular mass of BaSO4 is 137.3+(32.06+4*16.00)=233.4
Therefore the theoretical yield of Barium Sulphate is
233.4*0.01258=2.937 g
Actual yield = 2.60 g (given)
Therefore the percentage yield = 2.60/2.937=88.54%

Answer:
1. the limiting reagent is Barium Nitrate (Ba(NO3)2)
2. the theoretical yield is 2.94 g
3. the percentage yield is 88.5%

I apologize for the mistake previous to this update.

5 0

2 years ago