Calculate the gravitational force of attraction between a 26kg boy and his 5.1kg dog when they are separated by 0.19m

Chemistry

1 answer:

Pavel [41]2 years ago

6 0

Answer:

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

Explanation:

Given:

Mass M1 = 26 kg

Mass M2 = 5.1 kg

Distance r = 0.19 m

Find:

Gravitational force of attraction G(f)

Computation:

Gravitational force of attraction G(f) = G(m1)(m2)/r²

Gravitational force of attraction G(f) = [6.67 x 10⁻¹¹](26)(5.1)/(0.19)²

Gravitational force of attraction G(f) = 8.84 x 10⁻⁹ / 0.0361

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

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$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

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$\Delta H_{rxn}=[(3\times \Delta H_f_{(CH_4(g))})+(1\times \Delta H_f_{(CO_2(g))})+(4\times \Delta H_f_{(NH_3(g))})]-[(4\times \Delta H_f_{(CH_3NH_2(g))})+(2\times \Delta H_f_{(H_2O(l))})]$

We are given:

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