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iragen [17]
3 years ago
14

Do all quadratic equations have an axis of symmetry?

Mathematics
2 answers:
aleksley [76]3 years ago
8 0

Answer:yes

Step-by-step explanation:

bagirrra123 [75]3 years ago
5 0

Answer:

Yes,Axis of Symmetry of a Parabola.The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a.

Step-by-step explanation:

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12. Find the value of x.<br> HELP PLS HELP
xenn [34]

Answer:

x = 16

Step-by-step explanation:

 SR = ST ⇒ Two sides are equal. So, ΔSRT is an isosceles triangle.

The angles opposite to equal sides are equal.

  ⇒  ∠STR  = ∠R

       ∠STR = 4x - 28

Linear pair: If a ray stands on a line, then the adjacent angles are supplementary and they are called linear pair

∠STR + ∠STU = 180°    {linear pair}

4x - 28 + 9x = 180

4x + 9x - 28  = 180      {Combine like terms}

       13x- 28 = 180

Add 28 to both the sides

          13x    = 180 + 28

           13x  = 208

Divide both sides by 13

              x = 208/13

  \sf \boxed{x = 16}

8 0
2 years ago
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What is the answer to 5+ (6)(3)
BaLLatris [955]

Answer:

23 i think

Step-by-step explanation:

8 0
3 years ago
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Pls help there are 5 pics with multiple questions inside of them pls thank you
Bogdan [553]

Answer:

12. The second one

13. The first one

14. The last one

15. The first one

16. 30 degrees

Step-by-step explanation:

7 0
3 years ago
What is the vertex of y = x2 + 2x +2<br> O (1,-1)<br> O (2,-2)<br> O (1, 2)<br> 0 (-1, 1)
fredd [130]

Answer:

vertex = (- 1, 1 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = x² + 2x + 2 ← is in standard form

with a = 1 and b = 2 , then

x = - \frac{2}{2} = - 1

substitute x = - 1 into the equation for y- coordinate of vertex

y = (- 1)² + 2(- 1) + 2 = 1 - 2 + 2 = 1

vertex = (- 1, 1 )

8 0
3 years ago
Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

3 0
3 years ago
Read 2 more answers
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