One function you would be trying to minimize is
<span>f(x, y, z) = d² = (x - 4)² + y² + (z + 5)² </span>
<span>Your values for x, y, z, and λ would be correct, but </span>
<span>d² = (20/3 - 4)² + (8/3)² + (-7/3 + 5)² </span>
<span>d² = (8/3)² + (8/3)² + (8/3)² </span>
<span>d² = 64/3 </span>
<span>d = 8/sqrt(3) = 8sqrt(3)/3</span>
1a) The function has arrows on both ends and no place in the middle where it is not defined. Its domain is ...
All Reals
1b) The function gives no output values below -3, but it gives output values of -3 and all above that. Its range is ...
y ≥ -3
1c) For values of x less than -1, the function's output is 1. This matches g(x) and s(x). At x=0, the function's output is -3, which only matches g(x). The appropriate choice is ...
g(x)
2b) The function is only defined for 0 ≤ x < 8. This is its domain.
3) A definition might be ...
Answer: 2+q
Step-by-step explanation:
2/5 (-7) 5/2 as you know 2/5 x 5/2 = 1
so 1 x (-7) = -7
so the asnwer is -7
Answer:
No.
Step-by-step explanation:
1. Subsutute p/q with the numbers given, p = -2 and q = 5.
-2 / 5.
2. Divide 2/5 and -2/5 and compare.
2 / 5 = 0.40
-2 / 5 = -0.40
-0.40 < 0.40
If they are not =, then they are <u>NOT</u> equivalent.
Which means, they are Not equivalent.