What is a newton equal to in terms of units of mass and acceleration
2 answers:
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Answer:
The new period is approximately 3.93 × 10⁻⁷ h
Explanation:
The radius of the planet = 5 × 10⁶ m
The acceleration due to gravity on the planet, a = 10 m/s²
The period of the planet = 25 h
The centripetal force, , is given by the following equation;
Where;
v = The linear speed
r = The radius
Therefore, for the apparent weight, W, of an object to be zero, we have;
The weight of the object = The centripetal force of the object
W = Mass, m × Acceleration due to gravity, a
∴ W =
Which gives;
∵ r = The radius of the planet
We have;
v² = 10 × 5 × 10⁶
v = √(10 × 5 × 10⁶) ≈ 7071.07 m/s
The new frequency = Radius of the planet/(Linear speed component of rotation)
∴ The new frequency = 5 × 10⁶/(7071.07) = 707.107 revolutions per second
The new frequency = 707.107 × 60 × 60 = 2545585.2 revolutions per second
The new period = 1/Frequency ≈ 3.93 × 10⁻⁷ hour.
Answer:
a) E = K + Φ, b) ΔE = 1.64 10⁻¹³ J., c) λ = a
Explanation:
a) In this case it is an example of the photoelectric effect that was correctly described by Einstein assuming that the light ray is composed of a series of particles called photons, each one with an energy given by the Planck equation
E = h f
c = λ f
substituting
E = h c /λ
We can see from this equation that as the wavelength of the ray decreases the energy of each photon increases, the moment arrives that the energy is sufficient to remove an electron from the sphere, thus leaving an unbalanced positive charge, this description explains why the positive charge appears on the sphere; the minimum wavelength to remove an electron is
E = K + Φ
if K = 0
E =Φ
where fi is the work function of the material.
When the intensity of the ray increases according to Eintein's description, the number of photons increases, so if the number of photons increases, the number of shocks and the number of electrons expelled increases, therefore the unbalanced positive charge also increases.
b) the energy released in collision is the sum of the energy of each particle
for the electron
E = K + m c² = (pc) ² + (m c²) ²
where the moment is
p = γ m u
γ =
γ =
γ ≅ 1
in this case since the speed of the particles is much less than the speed of light,
E = (m u) ² + (m c²) ²
E = m² (u² + c²)
E = 9.1 10⁻³¹ [(2 10⁵) ² + (3 10⁸) ²
E = 9.1 10⁻³¹ 9 10¹⁶
E = 8.2 10⁻¹⁴ J
the positron has an energy of equal magnitude, so when the two particles annihilate the energy change is
ΔE = 2E
ΔE = 2 (8.2 10⁻¹⁴)
ΔE = 1.64 10⁻¹³ J.
c) the expression that describes the diffraction process is
a sin θ = m λ
sin θ = m λ/ a
where a is the width of the slit and m in diffraction order
The greatest value that the sine function can have is 1
1 = m λ / a
λ = a / m
therefore we can see that to see the diffraction phenomenon the width of the slit must be greater than or equal to the wavelength