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ddd [48]
3 years ago
8

Consider a makeup mirror that produces a magnification of 1.5 when a person's face is 11.5 cm away what is the focal length of t

he makeup mirror in meters?
Physics
1 answer:
LiRa [457]3 years ago
4 0

<u>Answer:</u> The focal length of makeup mirror is 0.3448 m.

<u>Explanation:</u>

We are given:

m = 1.5

u = -11.5 cm

To calculate the image distance, we the equation for mirror:

m=-\frac{v}{u}

Putting values in above equation, we get:

1.5=-(\frac{v}{-11.5})\\\\v=17.25cm

To calculate the focal length of mirror, we use the mirror formula, which is:

\frac{1}{f}=\frac{1}{v}+\frac{1}{u}

Putting values in above equation, we get:

\frac{1}{f}=\frac{1}{17.25}+\frac{1}{-11.5}\\\\f=-34.48cm

Negative sign represents the position of focal length.

Converting the focal length into meters, we use the conversion factor:

1 m = 100 cm

So, 34.48 cm = 0.3448 m

Hence, the focal length of makeup mirror is 0.3448 m.

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ella [17]

Answer:

The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules

Explanation:

The given spring constant of the of the spring, k = 88.0 N/m

The length by which the hose is stretched, x = 4.20 m

For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose

The elastic potential energy, P.E., of a compressed spring is given as follows;

P.E. = 1/2·k·x²

∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²

1/2 × 88.0 N/m × (4.20 m)² = 776.16 J

The work done on the hose = The potential energy given to hose, P.E. = 776.16 J

5 0
3 years ago
If the Mass Number is the sum of the protons and neutrons in an atom, what is<br> the mass number of
gogolik [260]

Answer:

It's 31

Explanation:

add 15 and 16

4 0
3 years ago
An alarm clock has a resistance of 14,000 ohms and is plugged into a 120-volt outlet. How much power does the clock use?
yan [13]

Power used by the clock=1.03 W

Explanation:

resistance= 14000 ohm

voltage=120 V

The formula for the power is given by

P=\frac{V^{2}}{R}

P=(120)²/14000

P=1.03 W

8 0
3 years ago
Read 2 more answers
A bird carrying a fish (5kg) drops it from 107 meters in the air how fast does the fish hit the ground
notka56 [123]

Answer:

The velocity of the fish hitting the ground is , v = 45.795 m/s        

Explanation:

Given data,

The mass of the fish, m = 5 kg

The height of the bird from the surface, h = 107 m

Using the III equation of motion,

                          v² = u² + 2gs

                          <em> v = √(u² + 2gs)</em>

Substituting the values,

                           v = √(0² + 2 x 9.8 x 107)  

                              = 45.795 m/s

Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s        

4 0
3 years ago
The Hubble Space Telescope has a mass of 1.16*10^ 4 kg and orbits the Earth at an altitude of 5.68 * 10 ^ 5 above Earth's surfac
andrezito [222]

Answer:

E=8.13\times 10^{12}\ J

Explanation:

Given that,

The mass of a Hubble Space Telescope, m_1=1.16\times 10^4\ kg

It orbits the Earth at an altitude of 5.68\times 10^5\ m

We need to find the potential energy the telescope at this location. The formula for potential energy is given by :

E=\dfrac{Gm_1m_e}{r}

Where

m_e is the mass of Earth

Put all the values,

E=\dfrac{6.67\times 10^{-11}\times 1.16\times 10^4\times 5.97\times 10^{24}}{5.68\times 10^5}\\\\E=8.13\times 10^{12}\ J

So, the potential energy of the telescope is 8.13\times 10^{12}\ J.

5 0
3 years ago
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