Answer:
True
Explanation:
Pioneer organisms are the first organisms that reoccupy a region that was destroyed by a disaster like flood, forest fire, volcanic eruptions, etc. These pioneer species can grow in the habitat that is barren and is not suitable for the growth and survival of other species.
Some of the pioneer species are lichens and algae. Pioneer species like lichens help in the formation of soil from breakdown or rocks which allow the formation of a suitable environment for the ecological succession of other species like mosses, algae, and other small plants. Therefore the statement is true.
Answer:
None of those, its called Soul Horizons
Explanation:
The answer is C The enzyme lowers the energy of activation for the reaction. The amount of free energy produced in the reaction increased with an enzyme. Energy of
Activation
Free energy
The requirement was established principally to address the growth of LISTERIA MONOCYTOGENES, which is a bacteria that has the capacity to continue growing even at refrigerated temperatures. The date marking procedure was put in place in order to make sure that the affected foods are discarded before the bacteria can initiate food borne illness.
Answer:
The correct answers are A. "crenation", B. "hemolysis", C. "hemolysis", D. "crenation" and E. "neither will occur".
Explanation:
0.9% (m/v) NaCl or 5.0% (m/v) glucose are isotonic solutions at which the cells will not suffer any harmful consequence. A solution with a higher concentration than the isotonic conditions would result in the cells crenation, while a solution with a lower concentration would result in the cells hemolysis. Therefore the consequences of putting the red cells to the solutions stated in the question are as following:
A: 3.21% (m/v) NaCl Solution = crenation (higher than 0.9% (m/v) NaCl)
B: 1.65% (m/v) glucose Solution = hemolysis (lower than 5.0% (m/v) glucose)
C: distilled H2O Solution = hemolysis (lower than 0.9% (m/v) NaCl or 5.0% (m/v) glucose)
D: 6.97% (m/v) glucose Solution = crenation (higher than 5.0% (m/v) glucose)
E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl = neither will occur (equal to 5.0% (m/v) glucose and 0.9% (m/v) NaCl)