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Oksanka [162]
3 years ago
13

How does radioactive isotopes decay?

Chemistry
1 answer:
aksik [14]3 years ago
7 0
They can decay through one of three ways: 
alpha decay
beta decay and
gamma decay
ALPHA- particle with two neutrons and two protons is ejected from the nucleus of the radioactive atom. this particle released is called an alpha particle. Only occurs with heavy metals.
BETA- pretty much when a proton is transformed into a neutron, or vise versa. in a beta minus decay, the nuetron decays into a proton and in a beta plus decay, a proton decays into a neutron
GAMMA- the nucleus changes from a high energy state to a low energy state by releasing electromagnetic radiation (photons). the number of protons and neutrons stay the same during this reaction therefore the element is still the same.
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Melts in the system pb-sn exhibit regular solution behavior. at 473°c apb = 0.055 in a liquid solution of xpb = 0.1. calculate t
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Given the temperature 746 K and activity of Pb equal to 0.055. The mole fraction of Pb is 0.1. So, the mole fraction of Sn = 0.9.Activity coefficient, γ = 0.055 / 0.1 = 0.55.The expression for w=ln⁡〖γ_Pb x RT〗/(X_Sn^2 )=(-0.5978 x 8.314 J/(mol K ) x 746 K)/(0.9 x 0.9)= -4577.7 J= -4578 J

Now we use the computed value above and new temperature 773 K. The mole fraction of Sn and Pb are 0.5 and 0.5 respectively. Calculate the activity coefficient in the following manner.lnγ_Sn=w/RT  X_Pb^2=(-4578 J)/(8.314 J/mol  x 773 K)  x 0.5 x 0.5= -0.718lnγ_Sn=exp⁡(-0.178)=0.386The activity of  Sn= γ_Sn  x X_Sn=0.386 x 0.5=0.418
w of the system is -4578 J and the activity of Sn in the liquid solution  of xsn at 500 degree Celsius is 0.418
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