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Leya [2.2K]
3 years ago
5

The volume of a sample of gas is 0.5 L and the pressure is 0.98 atm. The volume is increased to 1.0 L. Show the set

Chemistry
1 answer:
meriva3 years ago
5 0

Given,

P1 = 0.98 atm

V1 = 0.5 L

V2 = 1.0 L

P2 = ?

Solution,

According to Boyle's Law,

P1V1 = P2V2

0.98 × 0.5 = 1.0 × P2

P2 = 0.98 × 0.5 × 1.0

P2 = 0.49 atm

Answer - The new pressure is 0.49 atm.

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How many grams of h3po4 are in 255 ml of a 4.50 m solution of h3po4?
murzikaleks [220]

H3PO4 has molecular weight of approximately 98 grams per mole. 4.50 M is equal to 4.50 mole per 1000 mL solution of H3PO4. 255 mL times 4.50 mol /1000 mL times 98 g/mol is equal to 112.455 grams. Note that I automatically equate 1 Liter to 1000 mL since the given volume is in mL for easier computation.

7 0
3 years ago
A mixture is made of 40 ml of salt water to 200 ml of solution. What percent of the solution is salt water?
Serggg [28]

Answer:

16.7%

Explanation:

40 ml of salt water + 200 ml of solution = 240 ml

40/240 = 4/24 = 1/6=16.7%

5 0
3 years ago
How do you calculate the relative formula mass of a compound
RSB [31]
Write the formula of the compound.
Write the numbers of each atom in the formula. Insert the relative atomic mass for each type of atom. Calculate the total mass for each element.
Add up the total mass for the compound.
7 0
3 years ago
90 grams of NaNO3 were added to solution at 10 degrees Celsius. What type of solution was formed?
vichka [17]

Answer:

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4 0
3 years ago
Using the balanced equation, perform the stoichiometry calculations indicated in a. and b. below
Cloud [144]

Answer:

a) 113g Sr3(PO4)2

b) 1.5g H2

Explanation:

The number of moles of Sr used in the equation

= mass/ molar mass

=65.30/87

= 0.751mol

Since the mole ratio of Sr: Sr3(PO4)2 is 3:1

moles of Sr3(PO4)3 = 1/3*0.751

= 0.25mol

grams of Sr3(PO4)3 is = moles * molar mass

= 0.25 * 452

= 113g

b). Since mole ratio of Sr:H2 is 3:3

moles of H2 = 0.751 * 3/3 ---> 0.751 mol

grams of H2 is = moles * molar mass

= 0.751 * 2

= 1.502g

4 0
2 years ago
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