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3 years ago

The volume of a sample of gas is 0.5 L and the pressure is 0.98 atm. The volume is increased to 1.0 L. Show the set

Chemistry

1 answer:

meriva3 years ago

5 0

Given,

P1 = 0.98 atm

V1 = 0.5 L

V2 = 1.0 L

P2 = ?

Solution,

According to Boyle's Law,

P1V1 = P2V2

0.98 × 0.5 = 1.0 × P2

P2 = 0.98 × 0.5 × 1.0

P2 = 0.49 atm

Answer - The new pressure is 0.49 atm.

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How many atoms of chlorine are in the carbon tetrachloride molecule?

zaharov [31]

Answer:

4 atoms of Chlorine

Explanation:

This is actually easy to explain,

First we have here a type of nomenclature. This one is the sistematic nomenclature, and begins by naming the number of atoms that one element has, beggining for the non metal first, and then the metal or the non metal acting like a metal. In this case, the Carbon is acting like a metal.

The number of atoms are named by a prefix of the number. Each number has a determined prefix. Here are some of them:

one = 1 = mono

two = 2 = bi or di

three = 3 = tri

Four = 4 = tetra

Five = 5 = penta

Six = 6 = Hexa

So tetrachloride, means that we have 4 atoms of chlorine in the molecule and the molecule is this one: CCl4

7 0

3 years ago

Read 2 more answers

I need help so please help me

Kay [80]

Answer:b

Explanation:

I honestly don’t know if this I right but that would be my guess

3 0

3 years ago

If body fats has a density of 0.94 g/mL and 3.0 liters of fat are removed, how many pounds of fat were removed from the patient?

-Dominant- [34]

Answer:

6.217 pounds

Explanation:

We are given;

Density of body fats 0.94 g/mL
Volume of fats removed = 3.0 L

We are required to determine the mass of fats removed in pounds.

We need to know that;

Density = Mass ÷ volume

1 L = 1000 mL, thus, volume is 3000 mL

Rearranging the formula;

Mass = Density × Volume

= 0.94 g/mL × 3000 mL

= 2,820 g

but, 1 pound = 453.592 g

Therefore;

Mass = 2,820 g ÷ 453.592 g per pound

= 6.217 pounds

Thus, the amount of fats removed is 6.217 pounds

4 0

4 years ago

Which of the following is not an organic compound? Corn oil Bromine Methane Protein

zloy xaker [14]

The correct answer is Bromine
Hope this helped:)

6 0

3 years ago

Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit

ser-zykov [4K]

Answer:

For a: The edge length of the unit cell is 314 pm

For b: The radius of the molybdenum atom is 135.9 pm

Explanation:

For a:

To calculate the edge length for given density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density = $10.28g/cm^3$

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell =?

Putting values in above equation, we get:

$10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm$