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4 years ago

Enter the atomic symbol, including mass number and atomic number, for iodine-130.

Chemistry

1 answer:

WINSTONCH [101]4 years ago

6 0

Answer: The atomic symbol of the given element is $_{53}^{130}\textrm{I}$

Explanation:

The general isotopic representation of an element is given as: $_Z^A\textrm{X}$

where,

Z represents the atomic number of the element

A represents the mass number of the element

X represents the symbol of an element

For the given isotope: 130-iodine

Mass number = 130

Atomic number = 53

Hence, the atomic symbol of the given element is $_{53}^{130}\textrm{I}$

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1) The densities of air at −85°C, 0°C, and 100°C are 1.877 g dm−3, 1.294 g dm−3, and 0.946 g dm−3, respectively. From these data

earnstyle [38]

Answer:

1) The absolute zero temperature is -272.74 °C

2) The absolute zero temperature is -269.91°C

Explanation:

1) The specific volume of air at the given temperatures are;

At -85°C, v = 1/(1.877) = 0.533 dm³/g, the pressure =

At 0°C, v = 1/1.294 ≈ 0.773 dm³/g

At 100°C, v = 1/0.946 ≈ 1.057 dm³/g

We therefore have;

v₁ = 0.533 T₁ = 188.15 K

v₂ = 0.773 T₂ = 273.15 K

v₃ = 1.057 T₃ = 373.15 K

The slope of the graph formed by the above data is therefore given as follows;

m = (1.057 - 0.533)/(373.15 - 188.5) = 0.00284 dm³/K

The equation is therefor;

v - 0.533 = 0.00284×(T - 188.15)

v = 0.00284×T - 0.534 + 0.533 = 0.00284×T - 0.001167

v = 0.00284×T - 0.001167

Therefore, when the temperature, at absolute 0, we have;

v = 0

Which gives;

0 = 0.00284×T - 0.001167

0.00284×T = 0.001167

T = 0.001167/0.00284 ≈ 0.411 K

Which is 0.411 -273.15 ≈ -272.74 °C

The absolute zero temperature is -272.74 °C

2) The given volume of the gas = 20.00 dm³ at 0°C and 1.000 atm

The slope of the volume temperature graph at constant pressure = 0.0741 dm³/(°C)

The temperature is converted to Kelvin temperature, in order to apply Charles law as follows;

0°C = 0 + 273.15 K = 273.15 K

Therefore, the equation of the graph can be presented as follows;

v - 20.00 = 0.0741 × (T - 273.15)

Which gives;

v = 0.0741·T - 0.0741 ×(273.15) + 20

v = 0.0741·T - 20.2404125 + 20

v = 0.0741·T - 0.240415

Therefore at absolute 0, v = 0, we have;

0 = 0.0741·T - 0.240415

0.0741·T = 0.240415

T = 0.240415/0.0741 = 3.2445 K

The temperature in degrees is therefore;

3.2445 K - 273.15 ≈ -269.91°C

The absolute zero temperature is therefore, -269.91°C

3 0

4 years ago

Can you guys help me with my science homework??

algol [13]

Answer no 1)

The correct option is A) He did not try to learn it. It was natural.

As Sergei did not put any effort in learning the art of tongue rolling, hence we can assume that this characteristic was found to be naturally present in Sergei. This hence shows that Sergei has acquired the characteristic of tongue rolling through inheritance.

Answer No 2)

We can learn whether other persons in the class have the characteristic of tongue rolling or not by observing them. In the students who can roll their tongue we can conduct a survey asking them whether they tried to learn the trait or did not put any effort to learn tongue rolling. The students who learned the skill by practicing might have acquired the characteristic from learning.

Answer No 3)

We can survey the class for features like eye color, hair color, height, weight. We can ask certain questions in our survey like whether the characteristic can be seen in either the mother, father or other siblings.

4 0

3 years ago

How many liters are in 2.88 moles of CH4? Round your answer to the hundredths place (2 decimal place)

Kisachek [45]

64.50 because theirs 22.4L in one mole if u multiply that by 2 u get 64.51 u round that and get 64.50

5 0

3 years ago

Write a mechanism for the bromination of acetanilide with bromine in acetic acid. Be as complete as possible and include all rel

Karolina [17]

Answer:

See figure 1 and 2

Explanation:

In this case, we can start with the general reaction. Acetanilide with bromine in acetic acid we will produce p-bromo-acetanilide (See figure 1).

In the reaction mechanism, we have as first step the attack of the double bond in the benzene ring to one of the Br atoms in bromine ( $Br_2$ ) and a positive carbon will be produced in benzene. This positive charge can be moved inside of the benzne ring producing the resonance structures A, B and D. Resonance structure C is produced when a double bond is generating between the "N" atom and the carbon in the benzene ring.

The final step in the mechanism is when we remove the "H" atom in structure A to produce again the double bond.

See figure 2

I hope it helps!

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3 years ago

A student mixes 20.0 g of a salt in 100.0 g of water at 20 oC and obtains a homogeneous solution. Which salt could this be and w

olga nikolaevna [1]

Answer:

4) KNO₃ because is unsaturated.

Explanation:

The solubility of KCl in water at 20°C is 10.0g/100,0g and of KNO₃ is 30.0g/100.0g.

When you make a solution under these concentrations, the solutions will be saturated, higher concentrations gives heterogeneous solutions. Lowers concentrations gives homogeneous solutions.

As concentration of the solution made for the student is 20.0g / 100.0g:

If the solution is of KCl produce a heterogeneous solution because is oversaturated.

If the solution is of KNO₃ produce a homogenous solution because is unsaturated.

Thus, the solution is made of 4) KNO₃ because is unsaturated.

5 0

3 years ago