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3 years ago

Enter the atomic symbol, including mass number and atomic number, for iodine-130.

Chemistry

1 answer:

WINSTONCH [101]3 years ago

6 0

Answer: The atomic symbol of the given element is $_{53}^{130}\textrm{I}$

Explanation:

The general isotopic representation of an element is given as: $_Z^A\textrm{X}$

where,

Z represents the atomic number of the element

A represents the mass number of the element

X represents the symbol of an element

For the given isotope: 130-iodine

Mass number = 130

Atomic number = 53

Hence, the atomic symbol of the given element is $_{53}^{130}\textrm{I}$

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Answer:

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Explanation:

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3 years ago

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barxatty [35]

Answer:

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3.The electron affinity of $Mg^{2+}$ is zero.

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Explanation:

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The electron affinity of $S^{-}$ is as follows.

$S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

Ionization energy:

Amount of energy required to removal of an electron from an isolated gaseous atom.

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$Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

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Hence, it does not require more electrons to get stability.

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2 years ago

Metamorphic rocks that melt in a holt fluid can recystallize into a different form of rock

kotykmax [81]

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2 years ago

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erica [24]

Answer:

%age Yield = 51.45 %

Solution:

Step 1: Convert Kg into g

68.5 Kg CO = 68500 g CO

8.60 Kg H₂ = 8600 g

Step 2: Find out Limiting reactant;

The Balance Chemical Equation is as follow;

CO + 2 H₂ → CH₃OH

According to Equation,

28 g (1 mol) CO reacts with = 4 g (2 mol) of H₂

So,

68500 g CO will react with = X g of H₂

Solving for X,

X = (68500 g × 4 g) ÷ 28 g

X = 9785 g of H₂

It shows 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.

Step 3: Calculate Theoretical Yield

According to equation,

4 g (2 mol) H₂ reacts to produce = 32 g (1 mol) Methanol

So,

8600 g H₂ will produce = X g of CH₃OH

Solving for X,

X = (8600 g × 32 g) ÷ 4 g

X = 68800 g of CH₃OH

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%age Yield = Actual Yield ÷ Theoretical Yield × 100

Putting Values,

%age Yield = 3.54 × 10⁴ g ÷ 68800 g × 100

%age Yield = 51.45 %

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3 years ago