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svet-max [94.6K]

2 years ago

5

((HURRY PLLSS)) According to Einstein, nothing in the universe can move faster than which approximate speed?

1 answer:

sveticcg [70]2 years ago

4 0

Answer:

3.0 × 108 m/s

Explanation:

the speed of light

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What are the effects of gravity on earth?

Sliva [168]

Answer:

Without it, we could not survive on Earth. Earth orbits the sun due to the gravity of the sun, which maintains us at a convenient distance from it to enjoy the sun's warmth and light. It keeps the air we need to breathe and our atmosphere in place. Our planet is held together by gravity.

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1 year ago

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a. How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 25.0 cm in diameter t

Agata [3.3K]

Answer:

Explanation:

The electric field outside the sphere is given as,

E = k Q /r²

here Q = n x 1.6 x 10⁻¹⁹ C

where n is the number of electons

if the dimeter of sphere d= 25 cm= 0.25 m

then the radius r = 0.125 m

we get

n= E r²/ k x 1.6 x 10⁻¹⁹ C

n = 1350N/C x (0.125m)² / (8.99 x 10⁹ N m²/C² x 1.6 x 10⁻¹⁹ C)

n = 14664731646

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2 years ago

How is the acceleration of a car traveling on an elevated air track related to the angle of elevation and the height of elevatio

vitfil [10]

on a given inclined we know that net force is given by

$F_{net} = - mgsin\theta$

here we know that

$F_{net} = ma$

so here we have

$ma = - mg sin\theta$

$a = - gsin\theta$

so here acceleration depends directly on angle of inclination

now we also know that if height of the inclined is H and its length is L

then we can write

$sin\theta = \frac{H}{L}$

so the acceleration is given as

$a = - g*\frac{H}{L}$

so acceleration also depends directly on height of the inclined plane

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2 years ago

A venturi is constructed of a 10.0 cm pipe with a 2.0 cm diameter throat. Water pressure in the pipe is twice atmospheric pressu

postnew [5]

Answer:

$P_t=5066250.0696\ Pa=50\ atm$

Explanation:

Given:

diameter of pipe, $d=0.1\ m$

diameter of throat, $d_t=0.02\ m$

velocity of flow, $v=0.4\ m.s^{-1}$

<u>Pressure in the pipe is twice the atmospheric pressure:</u>

$P=2\times 101325=202650\ Pa$

<u>Now the force of flow of water:</u>

$F=P\times A$

<u>now we find cross sectional area of the pipe:</u>

$A=\frac{\pi.d^2}{4}$

$A=\pi \times\frac{0.1}{4}$

$A=0.007854\ m^2$

<u>Therefore,</u>

$F=202650\times 0.007854$

$F=1591.6094\ N$

<u>Now the area at throat:</u>

$A_t=\frac{\pi.d_t^2}{4}$

$A_t=\frac{\pi\times 0.02^2}{4}$

$A_t=0.000314\ m^2$

<u>Therefore pressure at throat:</u>

$P_t=\frac{F}{A_t}$

$P_t=\frac{1591.6094}{0.000314}$

$P_t=5066250.0696\ Pa=50\ atm$

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2 years ago

The wires connecting the switches, light-bulbs and buzzers must start and end at the power source before the circuit can work. T

MakcuM [25]

A IS THE FINAL ANSWER :)

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3 years ago

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