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Len [333]
3 years ago
14

What causes the earths plates to move

Physics
2 answers:
Norma-Jean [14]3 years ago
8 0
The intense heat in the earth's core that causes molten rock in the mantle layer to move.
Kaylis [27]3 years ago
3 0

Answer: The intense heat

Explanation:

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Spider-Man and Ned were testing the distance he could shoot his web depending on the angle at which he points his web shooter. H
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If a roller coaster cart, with a mass of 100 kg, traveled this coaster, how much kinetic energy would it have at point 'E'?
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Answer:

Explanation:

Assuming no friction between the roller coaster car and the hill, and neglecting air resistance, the kinetic energy the roller coaster car would have at the bottom of the hill would be equal to its gravitational potential energy at the top of the hill, by conservation of energy.

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3 years ago
The diagram below outlines the appeals path through a state court system.
dexar [7]

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B sorry if im wrong

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3 years ago
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An electric drill rated at 400 W is connected to a 240V power line. How much current does it draw?
disa [49]

Answer:

1.67 A

Explanation:

Given that,

→ Power (P) = 400 W

→ Potential difference (V) = 240 V

→ Current (I) = ?

The amount of current drawn will be,

→ P = V × I

→ I = P/V

→ I = 400/240

→ I = 1.66666666667

→ [ I = 1.67 A ]

Hence, the current drawn 1.67 A.

8 0
2 years ago
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The flywheel is rotating with an angular velocity ω0 = 2.37 rad/s at time t = 0 when a torque is applied to increase its angular
nika2105 [10]

Answer:

ω = 12.023 rad/s

α = 222.61 rad/s²

Explanation:

We are given;

ω0 = 2.37 rad/s, t = 0 sec

ω =?, t = 0.22 sec

α =?

θ = 57°

From formulas,

Tangential acceleration; a_t = rα

Normal acceleration; a_n = rω²

tan θ = a_t/a_n

Thus; tan θ = rα/rω² = α/ω²

tan θ = α/ω²

α = ω²tan θ

Now, α = dω/dt

So; dω/dt = ω²tan θ

Rearranging, we have;

dω/ω² = dt × tan θ

Integrating both sides, we have;

(ω, ω0)∫dω/ω² = (t, 0)∫dt × tan θ

This gives;

-1[(1/ω_o) - (1/ω)] = t(tan θ)

Thus;

ω = ω_o/(1 - (ω_o × t × tan θ))

While;

α = dω/dt = ((ω_o)²×tan θ)/(1 - (ω_o × t × tan θ))²

Thus, plugging in the relevant values;

ω = 2.37/(1 - (2.37 × 0.22 × tan 57))

ω = 12.023 rad/s

Also;

α = (2.37² × tan 57)/(1 - (2.37 × 0.22 × tan 57))²

α = 8.64926751525/0.03885408979 = 222.61 rad/s²

6 0
3 years ago
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