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vichka [17]
3 years ago
13

Help me do this question ​

Physics
1 answer:
Zepler [3.9K]3 years ago
3 0

Answer:

c20800

Explanation:

go to bear khana bro your book looks cheap go and study in durbar kanda school and take somee cash and do ash ah boy

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Which of the followings are true about Vmax? A. The higher the [enzyme], the higher the Vmax B. Vmax is proportional to k2 C. Vm
Vera_Pavlovna [14]

Answer:

Correct answer is A.

The higher the enzyme, the higher the Vmax

Explanation:

Although, in the absence of enzyme, the rate of a reaction(Vmax) increase linearly with substrate concentration. The reaction rate is given as dp/dt.

The rate of a reaction involving enzyme also increases.

At low enzyme concentrations or high substrate concentrations, all of the available enzyme active sites could be occupied with substrates. Therefore, increasing the substrate concentration further will not change the rate of diffusion. In other words, there is some maximum reaction rate (Vmax) when all enzyme active sites are occupied. The reaction rate will increase with increasing substrate concentration, but must asymptotically approach the saturation rate, Vmax. Vmax is directly proportional to the total enzyme concentration, E

5 0
3 years ago
Which one is the right andwerrrrrrrr
Elden [556K]
2nd one I believe! If I’m wrong sorry
7 0
3 years ago
A flat circular loop of wire of radius 0.50 m that is carrying a 2.0-A current is in a uniform magnetic field of 0.30 T. What is
Luba_88 [7]

Answer:

The magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

Explanation:

Given;

radius of the circular loop of wire = 0.5 m

current in circular loop of wire = 2 A

strength of magnetic field in the wire = 0.3 T

τ = μ x Bsinθ

where;

τ is the magnitude of the magnetic torque

μ is the dipole moment of the magnetic field

θ is the inclination angle, for a plane area perpendicular to the magnetic field, θ = 90

μ = IA

where;

I is current in circular loop of wire

A is area of the circular loop = πr² = π(0.5)² = 0.7855 m²

μ = 2 x 0.7885 = 1.571 A.m²

τ = μ x Bsinθ =  1.571 x 0.3 sin(90)

τ = 0.4713 J

Therefore, the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J

4 0
4 years ago
Temperature is perhaps the most important factor in the distribution of organisms because
Maurinko [17]

Answer:

True

Explanations

Temperature is the degree of coldness or hotness of a body, usually organism rarely adapt to extreme temperature value of below 0°C or above 43°C,organisms usually respond to cold weather by hibernation or estivation for hot weather also extreme temperature causes migration of birds if they can't survive such place like the artic tern that travel thousands of miles,

3 0
3 years ago
The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t
slamgirl [31]

Answer:

The charge is 2.75\times10^{-13}\ C

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length L=5.0\times5.0\times10^{-4}\ m

We need to calculate the linear charge density

Using formula of linear charge density

E=\dfrac{2k\lambda}{r}

\lambda=\dfrac{Er}{2k}

Put the value into the formula

\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}

\lambda=1.1\times10^{-10}\ C/m

We need to calculate the charge

Using formula of charge

Q=\lambda\timesL

Put the value into the formula

Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})

Q=2.75\times10^{-13}\ C

Hence, The charge is 2.75\times10^{-13}\ C

5 0
3 years ago
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