Question

A diver jumps up off a pier at an angle of 25° with an initial velocity of 3.2 m/s. How far from the pier will the diver hit the water? (Assume the level of the water us the same as the pier)

Answer 1

Answer:

0.8 meters.

I just answered this ame question myself on a test I was taking.

Answer 2

Answer:

0.80m

Explanation:

The problem requires that we calculate the range covered by the diver, here the diver is assumed to be a particle undergoing projectile motion.

The range, R is given by equation (1);

$R=\frac{u^2sin2\theta}{g}......................(1)$

where u is the initial velocity, $\theta$ is the angle of projection and g is acceleration due to gravity which is taken as $9.8m/s^2$.

Given;

u = 3.2m/s and $\theta=25^o$.

Substituting these into equation (1), we obtain the following;

$R=\frac{3.2^2sin2(25)}{9.8}\\R=\frac{10.24*sin50}{9.8}\\R=\frac{10.24*0.7660}{9.8}\\R=0.80m$