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3 years ago

Gravitational pull between 2 objects is determined by which of the following?

Physics

2 answers:

sp2606 [1]3 years ago

8 0

Answer:

Both distance between and mass of the 2 objects

Explanation:

The gravitational pull between two objects is given by:

$F=G\frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

m1 is the mass of the first object

m2 is the mass of the second object

r is the distance between the two objects

From the formula, we see that the gravitational pull depends both on the distance between the two objects (r) and on their masses (m1, m2), so the correct answer is

Both distance between and mass of the 2 objects

vampirchik [111]3 years ago

3 0

Both distance between and mass of the 2 objects.

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A force of 10 N making an angle 30 with horizontal .its horizontal component wll be

Norma-Jean [14]

Answer:

10 cos (30)N

Explanation:

So, if we were to visualize it for a sec

we would see 10 as the hypotenuse, 30 as the angle between and would be solving for the adjacent side

So, using basic trig rules,

using the fact that cos(30)=x/10

x=10 cos (30)N

7 0

3 years ago

Part A: A group of students performed the same "Ohm's Law" experiment that you did in class. They obtained the following results

pentagon [3]

Answer:

Kindly check explanation

Explanation:

Given the data:

Trial V (volts) I (mA)

1 1.00 7.2

2 2.10 14.0

3 3.10 20.7

4 4.00 27.2

5 4.90 32.2

Slope = Rise / Run

Rise = y2 - y1 = 32.2 - 7.2 = 25

Run = x2 - x1 = 4.9 - 1.0 = 3.9

Slope = 25 / 3.9 = 6.410

y = mx + c

The intercept, c

Take the point ( 1; 7.2)

Put x = 0

7.2 = 6.410(1) + C

7.2 - 6.410 = C

C = 0.79

3 0

3 years ago

Please help on this one?

vlada-n [284]

Answer:

idk

Explanation:

7 0

3 years ago

Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a

In-s [12.5K]

Answer:

$T = 1.108\,s$

Explanation:

The period of a physical pendulum is:

$T = \sqrt{\frac{I_{O}}{m\cdot g \cdot L} }$

$T=2\cdot \pi \sqrt{\frac{\frac{1}{3}\cdot m \cdot L^{2} }{m\cdot g\cdot L} }$

$T=2\cdot \pi \sqrt{\frac{L }{3\cdot g} }$

The length of the leg is approximately the height of the person:

$L = 0.915\,m$

The period is:

$T = 2\cdot \pi \sqrt{\frac{0.915\,m}{3\cdot (9.807\,\frac{m}{s^{2}} )} }$

$T = 1.108\,s$

4 0

3 years ago

If the octupus had twelve arms then how many arms would the crab have show your work

Alexandra [31]

Answer:

I believe that the crab would have 14 arms if the octopus had 12 arms

Explanation:

4 0

3 years ago