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zvonat [6]
3 years ago
9

Which of the following does not represent a question that can be answered by science?a. How much energy is released in a given n

uclear chain reaction? b. Can a nuclear chain reaction be controlled? c. Should uncontrolled nuclear reactions be used for military applications?
d. What is the half-life of a waste product of a nuclear reaction?
Physics
2 answers:
Nookie1986 [14]3 years ago
6 0

Answer:

c.

Explanation:

LenaWriter [7]3 years ago
4 0

Answer:

c. Should uncontrolled nuclear reactions be used for military applications?

Explanation:

The question on wether to use technology for military applications, is not a science question but a moral dilemma

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Two men standing on the same side of wall and at the same distance from It, such that they are 4oom apart when one fires a gun t
Mamont248 [21]

Answer:

1. 571.43m/s

2. 142.9m and 342.9m

Explanation:

1.Take the difference in time.

1.2-0.7=0.7 seconds

Take the distance between them and divide with differnce in time.

400÷0.7=571.43 seconds.

2.Take the time of the two men and divide by two.

0.5÷2= 0.25 secs

1.2÷2= 0.6 secs

multiply each with the velocity.

0.25×571.43=142.9m

0.6×571.43=342.9m

8 0
2 years ago
Choose correct answer
rodikova [14]
C is the correct answer urwelcom
7 0
3 years ago
Read 2 more answers
at a constant pressure at a temperature of 280 k the gas in the cylinder has the volume of 10 liters if the volume of the gas is
Sav [38]
Since there is constant pressure, you can use Charles's Law:

V1/T1 = V2/T2

10L/280K = 20L/T

0.0357 = 20/ T

T = 20/0.0357

T = 560K which is the new temperature
7 0
3 years ago
A cylindrical piece of wood of height H, radius r, and uniform density rhoc is bobbing up and down in still water with its axis
Keith_Richards [23]

Answer:

r\sqrt{\frac{g\pi\rho_w}{m}}

Explanation:

As the buoyant force is proportional to the length of which the wood is submerged in water, we can model the buoyant force as a spring force and the bobbing wood is a simple harmonic motion described as A cos (ωt + φ) where

\omega = \sqrt{\frac{k}{m}}

where k (N/m) is the "spring" buoyant constant and m is the mass of wood

The buoyant force is basically the weight of water displaced by the submerged wood, which is the gravity acting on the cylindrical volume

F_b = W_w = m_wg = V_w\rho_w g

Since the cylindrical has a form of AL where A is the base area and L is the length submerged

F_b = AL\rho_w g = (\pi r^2\rho_w g) L

As L can be treated as the spring "stretched/compressed" length, the rest is k:

F_b = kL = (\pi r^2\rho_w g) L

k = (\pi r^2\rho_w g)

Therefore

\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{\pi r^2\rho_w g}{m}} = r\sqrt{\frac{g\pi\rho_w}{m}}

8 0
3 years ago
50 POINTS! pls answer
fredd [130]

Thanks for points...

But can you type this question.. As it becomes hard to answer if it's in the picture..

4 0
3 years ago
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