I’m going to assume initial velocity is 0.
Use Newton’s second law:
F = m•a
F/m = a
14.0/32.5kg= 28/65 m/s^2
Use constant SUVAT acceleration formulae:
S- displacement - what we need to find out
U - initial velocity - 0
V
A - 28/65 m/s^2
T - 10 seconds
S = ut + 1/2at^2
Since u = 0
S = 1/2at^2
1/2• 28/65 • 10^2 = 21.5metres~
Answer is 21.5 metres
~Hoodini, here to help.
Answer:
It is the point at which electrons separate from the nucleus of atoms. It is the point at which electrons separate from the nucleus of atoms. It is theoretically the point at which all particle motion stops. ... It occurs at 273 degrees Kelvin. ... It is the point at which protons separate from neutrons in the nucleus.
Explanation:
First off, Newton's second law<span> of motion is the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
So therefore, it would be a force is being applied to the mass</span>
In a solid particles vibrate back and forth
