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alex41 [277]
3 years ago
9

What is Metallurgy and different types of metal extracting process?????

Chemistry
1 answer:
Anna35 [415]3 years ago
6 0
THE EXTRACTION OF METALS FROM THEIR RESPECTIVE ORES IS KNOWN AS METALLURGY.
THE DIFFERENT PROCESS ARE :- ROASTING, CALCINATION, FROTH FLOTATION AND MGNETIC SEPARATION.
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Please help! It’s due today. I’ll give brainliest
MArishka [77]

Answer:

look at it is the correct answer because if a new gas has formed bubbles will how or change of colour so look at it

Explanation:

5 0
3 years ago
Read 2 more answers
A 25.0 mL sample of H3PO4 requires 50.0 mL of 1.50 M NaOH for complete neutralization. What is the molarity of the acid?
Kamila [148]

Answer:

The molarity of acid is 3 M.

Explanation:

Given data:

Volume of H₃PO₄ = 25 mL

Volume of NaOH = 50 mL

Molarity of NaOH = 1.50 M

Molarity of  H₃PO₄ = ?

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = M₂V₂ / V₁

M₁ = 1.50 M ×50 mL / 25 mL

M₁ = 75 M. mL / 25 mL

M₁ = 3 M

The molarity of acid is 3 M.

8 0
4 years ago
Which of these are components of DNA? Check all that apply.
Kipish [7]

Answer:

  1. deoxyribose sugar molecules.
  2. adenine.
  3. cytosine.
  4. thymine.
  5. phosphate molecules.

Explanation:

Hope it helps.

6 0
4 years ago
Calvert likes to paddle around in his canoe. One day it sprung a leak and started to fill with water. Luckily, Calvert was able
allochka39001 [22]
The hole in the boat caused it to take on water, as the boat filled with water, it became less and less buoyant, eventually filling with water until losing buoyancy completely and sinking.
5 0
3 years ago
How many moles of gas are contained in a 50.0 L cylinder at a pressure of 100.0 atm and a temperature of 35.0°C?
grigory [225]

Answer:

n = 2 moles (1 sig-fig)

Explanation:

Using the Ideal Gas Law equation (PV = nRT), solve for n (= moles) and substitute data for ...

pressure = P(atm) = 100atm

volume =V(liters) = 50L

gas constant = R = 0.08206L·atm/mol·K

temperature = T(Kelvin) = °C + 273 = (35 + 273)K = 308K

PV = nRT => n = PV/RT = (100atm)(50L)/(0.08206L·atm/mol·K)(308K)

∴ n(moles) = 1.978moles ≅ 2 moles gas (1 sig-fig) per volume data (= 50L) that has only 1 sig-fig. (Rule => for multiplication & division computations round final answer to the measured data having the least number of sig-figs).

7 0
3 years ago
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