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charle [14.2K]
3 years ago
10

Please help! It’s due today. I’ll give brainliest

Chemistry
2 answers:
MArishka [77]3 years ago
5 0

Answer:

look at it is the correct answer because if a new gas has formed bubbles will how or change of colour so look at it

Explanation:

zavuch27 [327]3 years ago
3 0
Iiiiii you guys have to have the kids tomorrow so you
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A solution of sulfuric acid (H2SO4, 25.00 mL) was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What was th
Karolina [17]

Answer:

0.0705 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, H₂SO₄ (nA) = 1

The mole ratio of the base, NaOH (nB) = 2

Next, data obtained from the question. This include the following:

Volume of acid, H₂SO₄ (Va) = 25 mL

Volume of base, NaOH (Vb) = 34.55 mL

Molarity of base, NaOH (Mb) = 0.1020 M

Molarity of acid, H₂SO₄ (Ma) =?

The molarity of the acid, H₂SO₄ can be obtained as follow:

MaVa / MbVb = nA/nB

Ma × 25 / 0.1020 × 34.55 = 1/2

Ma × 25 / 3.5241 = 1/2

Cross multiply

Ma × 25 × 2 = 3.5241

Ma × 50 = 3.5241

Divide both side by 50

Ma = 3.5241 / 50

Ma = 0.0705 M

Therefore, the concentration of the acid, H₂SO₄ is 0.0705 M

4 0
3 years ago
Read 2 more answers
A water reclamation plant turns sewage water directly into drinking water.
yulyashka [42]
<span>A water reclamation plant turns sewage water directly into drinking water. 
a. true 
b. false

The answer is true.</span>
3 0
3 years ago
an object with a larger mass requires greater force to accelerate than an object with a smaller mass true or false?
mr Goodwill [35]

Answer:

true

Explanation:

because of its weight

5 0
3 years ago
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Pb(NO3)2+K2CrO4=PbCrO4+KNO3 reaction type​
Dmitry [639]
Precipitation reaction and double displacement reaction
7 0
3 years ago
The mole fraction of NaCl in an aqueous solution is 0.132. What is the weight/weight percent of NaCl in this solution?
Marrrta [24]

Answer:

\% w/w=33.1\%

Explanation:

Hello,

In this case, since the solution is formed by sodium chloride and water, we understand that for one mole of solution, we have 0.132 moles of sodium chloride and 0.868 moles of water, therefore, by using their molar masses we can compute their masses in the solution:

m_{NaCl}=0.132molNaCl*\frac{58.44gNaCl}{1molNaCl}=7.714gNaCl\\ \\m_{H_2O}=0.868molH_2O*\frac{18gH_2O}{1molH_2O}=15.624gH_2O

Thereby, we can compute the weight/weight percent as follows:

\% w/w=\frac{m_{NaCl}}{m_{H_2O}+m_{NaCl}}*100\%

So we use the previously computed masses:

\% w/w=\frac{7.714g}{7.714g+15.624g}*100\%  \\\\\% w/w=33.1\%

Best regards.

4 0
4 years ago
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