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mr Goodwill [35]
3 years ago
15

Which two statements are true about energy transformations

Physics
2 answers:
Lorico [155]3 years ago
8 0

Answer:

First statement is that the total mechanical energy in a close system is always constant.

Second statement is that energy can change from one form to another. e. g from potential energy to kinetic energy

Explanation:

First statement is that the total mechanical energy in closed system is always constant.

Second statement is that energy can change from one form to another.e.g potential energy to kinetic energy.

inn [45]3 years ago
3 0
Hey luv, what’s the two statements?
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What is the acceleration of an arrow that has a mass of 0.1 kg and a force of 9 N?
djverab [1.8K]

Force = Mass x Acceleration

9N = 0.1kg x Acceleration

Acceleration = 9N / 0.1kg

Acceleration = 90 m/s^2

4 0
3 years ago
How much would a 70 kg student weigh on Pluto? (massPluto = 1.25 x 1022 kg, radiusPluto = 1.20 x 106 m)
mote1985 [20]

Answer: the weight would be 4.6 (I think i don’t know))

Explanation:

6 0
3 years ago
Pure water has a hydrogen ion concentration of 1 x 10 (-7) M and a ph of 7. A student measures a basic solution and finds that i
Lena [83]

The student must have made an error in her measurement in the concentration of hydrogen ion in the basic solution given. From her measurement, the concentration is  1 × 10−3 M. If we calculate the pH, we get:

pH = -log ( 1 × 10−3) = 3

A pH of 3 does not signifies a basic solution it is in the acidic range. So, the measurement is wrong.

6 0
4 years ago
A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o
dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is  m_1 = 81.14 \ kg

Explanation:

From the question we are told that

   Mass of the first block is  m_1 = 100 \  kg

   The height is  s =  1.0 \  m

   The time it takes it is  t = 1.40 \  s

 Generally from kinematic equation

       s =  ut + \frac{1}{2} at^2

Here u  is the initial velocity which zero given that it was at rest initially

So

     s =  0 * t + \frac{1}{2} at^2

=>  s =   \frac{1}{2} at^2

=> 1 =   \frac{1}{2}*  a *  (1.40 )^2

=>  a = 1.0204 \  m/s^2

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is  mathematically represented as

      mg - T = ma

=>   T  =  m g - ma

=>   T  =  m(g - a)

=>   T  =  877.96 \  N

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is  mathematically represented as  

     T - m_1g  =  m_1 a

=>   877.96  =  m_1 (a + g)

=>   877.96  =  m_1 (1.0204  + 9.8 )

=>   m_1 = 81.14 \ kg

5 0
3 years ago
Movement of a stationary object
Setler [38]

I would say that you're describing an impossible situation.
If the object is stationary, then it has no movement.
If the object has movement, then it's not stationary.

5 0
4 years ago
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