How does a mirror affect the path of light?

1 answer:

8 0

Light rays change direction when they hit a mirror. The phenomenon is known as reflection. Light rays travels in a straight light. They strike the surface of the mirror at a particular angle called incident angle. It is the angle between the ray and normal at the point of contact. The rays leaves the surface making the same angle with the normal called reflection angle but in different direction.

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An object is dropped near the earth's surface. At the end of 4.0 s, how fast is it falling in m/s? (Ignore air resistance.)

Sati [7]

For free falling bodies, the final velocity may be calculated through the equation,
Vf = gt
Where g is the acceleration due to gravity (9.8 m/s²) and t is the time elapsed. Substituting the known values,
Vf = (9.8 m/s²) x (4 s) = 39.2 m/s
Therefore, the object's velocity is approximately 39.2 m/s.

7 0

3 years ago

Read 2 more answers

A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE g

Anna35 [415]

Answer:

a) $r_1=1.36R$

b) $r_2=2.083R$

Explanation:

<u>Given:</u>

a) when the initial velocity of the projectile is 0.520 times the escape velocity from the earth.

Let r be the radial distance from the earth's surface Let M be the mass of the Earth and R be the radius of the Earth

Now using conservation of Energy at earths surface and at distance r we have

$\dfrac{-GMm}{R}+\dfrac{m(0.52V_e)^2}{2}=\dfrac{-GMm}{r_1}\\\dfrac{-GMm}{R}+\dfrac{m\times 0.52^2\times \dfrac{2GM}{R}}{2}=\dfrac{-GMm}{r_1}\\r_2=1.36\ R$

b) when the Initial kinetic Energy of the projectile is 0.52 times the Kinetic Energy required to escape the Earth

Conservation of Energy we have

$\dfrac{-GMm}{R}+0.52\times KE_{escape}=\dfrac{-GMm}{r_2}\\\dfrac{-GMm}{R}+0.52\times\dfrac{m\times \dfrac{2GM}{R}}{2}=\dfrac{-GMm}{r_2}\\r_2=2.083\ R$

3 0

3 years ago

When a person jumps from tree to ground, what happens to the momentum of the person upon striking the ground? ...?

Ludmilka [50]

When a person jumps from a tree to ground, what happens to the momentum of the person upon striking the ground is that it is transferred to earth. The momentum is not lost, it is conserved by being transferred to the ground. But it can also be lost to the impulse.

4 0

2 years ago

(3)science who ever gets this right will get a brainlest

lara [203]

Answer:

True.

Explanation:

It also affects your lungs by getting lung disease.

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2 years ago

While standing on a bridge 40.0 m above the ground, you drop a stone from rest. when the stone has fallen 3.80 m, you throw a se

Norma-Jean [14]

Given: distance 1 d₁ = 40 m; distance 2 d₂ = 3.8 m g = -9.8 m/s²

Initial Velocity Vi = 0 Final Velocity of stone 2 is unknown = ?

Total distance dₓ = d₁ - d₂ = 40 m - 3.8 m = 36.2 m

Formula: a = Vf² - Vi²/2d derive for Final Velocity Vf

acceleration is now due to gravity, therefore a = g

Vf = √2gd Vf = √2(9.8 m/s²)(36.2 m)

Vf = 26.64 m/s

Reason: The second stone will still start from rest.

3 0

3 years ago