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erastovalidia [21]
3 years ago
15

A 2.00-kg object traveling east at 20.0 m/s collides with a 3.00-kg object traveling west at 10.0 m/s. After the collision, the

2.00-kg object has a velocity 5.00 m/s to the west. How much kinetic energy was lost during the collision?
Physics
2 answers:
garri49 [273]3 years ago
5 0
Lost K.E.= Final K.E. - Initial K.E.
ΔK.E. = 1/2 mv₁² - 1/2 mv₂²
ΔK.E = 1/2 m [v₁²-v₂²]
ΔK.E = 1/2 * 2 * [20-5]
ΔK.E = 1 * 15
ΔK.E = 15 Joules

So, your final answer is 15 Joules.
nikitadnepr [17]3 years ago
3 0
I think u hv to use conservation of momentum formula
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