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emmainna [20.7K]
2 years ago
14

How many 6 inches long tiles will fit on a back splash that is 8 ft long

Mathematics
1 answer:
Blizzard [7]2 years ago
8 0
16 tiles will fit on a back splash that is 8ft long
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PLEASE HELP I AM ON A TIME LIMIT
Alinara [238K]

Answer:

  (a) even: J, K, M, O; odd: L, N

  (b) L and O are connected to J

  (c) N is of degree 3

Step-by-step explanation:

Count the edge ends that intersect each vertex. You get ...

  J-2, K-2, L-3, M-2, N-3, O-4

These numbers are the <em>degree</em> of the vertex.

a) Vertices with even degree are J, K, M, O, since these have degrees of 2, 2, 2, and 4, respectively--all even numbers.

Vertices with odd degree are L and N, since these both have degree 3, an odd number.

__

b) The vertices that are adjacent to J are the ones at the other ends of the edges that intersect vertex J. One of those two edges connects to vertex L; the other to vertex O. J is adjacent to L and O.

__

c) When we counted edges in part (a), we found vertex N to be of degree 3.

5 0
2 years ago
Sylvanite is a mineral that contains 28.0% gold by mass. Determine how much sylvanite would you need to dig up to obtain 81.0 g
lidiya [134]
Since Sylvanite only contains 28% gold by mass, then to obtain 81.0 grams of gold, x amounts of sylvanite must be mined. To determine x, we divide 81 grams by 28%. This equation is shown below:

0.28X = 81

X = 81/0.28
X = 289.29 grams

Therefore, 289.29 grams of sylvanite must be dug up to obtain 81 grams of gold.
3 0
3 years ago
What is 1/5 + 3/10 ??
Anarel [89]

Answer:

first we will make them like fractions

so 1/5= 2/10 so it will be

2/10+3/10= 5/10

HOPE IT HELPS

mark as brainliest

7 0
3 years ago
What the answer I don’t know it
meriva
The answer is B since a negative number being subtracted cancels out and becomes a number, for example: since its -(-3) it becomes positive.
5 0
3 years ago
Read 2 more answers
Evaluate 15/5 + 40 . 7 - 3 to the power of 4.
Lina20 [59]
15/5 + 40.7 -3^4
= 3 + 40.7 - 81
= -37.3


hope this helps! :)))
4 0
3 years ago
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